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blondinia [14]
3 years ago
12

F(x) = 14 -0.5x f(30)=

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

You would substitute all x's with the number 30, so the answer would be f(30)=-1 or y=-1

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Write the decimal 1,072.039 in words
Rina8888 [55]
One thousand seventy two point thirty nine thousandths.

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If f(x) = -2x^2 + 1 and g(x) = 3x, evaluate f(x) / g(x) for x = 2
adelina 88 [10]
I think that the answer is A.
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7. Write an equation for the line that is parallel to the given line and that passes through the given point.
Vlad1618 [11]

Answer:

C. y = 1/2x - 14

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  y = 1 /2 x − 8 .

y = 1 /2 x − 14                              PARALLEL

...................................................................................................................................................

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  y = 1 /2 x − 8 .

y = − 2 x − 29                               PERPENDICULAR

8 0
2 years ago
Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex
algol13

9514 1404 393

Answer:

  a) x = (√5 -1)/2 ≈ 0.618034

  b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

<u>Given</u>:

  x/(1 -x) = 1/x

<u>Find</u>:

  Exactly, and as a decimal approximation, ...

  a) x, using the quadratic formula

  b) 1/x

<u>Solution</u>:

a) We can multiply the given equation by x(1 -x) to obtain ...

  x² = 1 -x

  x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}

We are only interested in the positive solution, which is ...

  \boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}

__

b) The quadratic we developed in the first part can be rearranged like this:

  x² +x = 1 . . . . . . add 1 to both sides

  x(x +1) = 1 . . . . . factor out x

  x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

  \dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}

5 0
3 years ago
Help me please !!!!
morpeh [17]

Answer:

1. Two endpoints. 2. Always. 3.Always

Step-by-step explanation:

7 0
3 years ago
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