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2 years ago

Si un número es múltiplo de 3, también es de 9? Expliquen por favor.

Mathematics

1 answer:

klio [65]2 years ago

4 0

Si un número es múltiple de 3 también es de 9? El problema van así 27

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What is the length ?

Brums [2.3K]

Answer:

AC = 2x - 13 Cm

BC = 3x + 4 Cm

AB = 36 Cm

AB = AC + BC

BC = AB - AC

= 36 - (2x - 13)

= 36 - 2x + 13

= 49 - 2x

but, BC = 3x + 4

so equating both the equation we get

3x + 4 = 49 - 2x

3x + 2x = 49 + 4

5x = 53

x = 53/5

x = 10.6

BC = 49- 10.6*2

= 49- 21.2

= 27.8 CM

8 0

1 year ago

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Tina decides to measure how the amount of force (in newtons) that concrete can withstand changes as the surface area over which

Bumek [7]

Answer:

N/m^2

Step-by-step explanation:

If the amount of force (newtons) is changing over the surface area, that means we should use units in the form of newtons over surface area, which is in the form of m^2.

4 0

3 years ago

Read 2 more answers

Can you help me solve this please

OLga [1]

Answer:

-22+27i

Step-by-step explanation:

$i = \sqrt{ - 1} \\ (3 - 4i)( - 6 + i) \\ = (3 - 4 \sqrt{ - 1} )( - 6 + \sqrt{ - 1} ) \\ = 3( - 6 + \sqrt{ - 1)} - 4 \sqrt{ - 1} ( - 6 + \sqrt{ - 1} ) \\ = - 18 + 3 \sqrt{ - 1} + 24 \sqrt{ - 1} - 4 \\ = - 22 + 27 \sqrt{ - 1} \\ putting \: \: \: \sqrt{ - 1 } = i \\ = - 22 + 27i$

Hope it helps.

Don't forget to click the Brainliest button if you like my answer.

8 0

2 years ago

5.63 round to nearest tenth

White raven [17]

5.6 is 5.63 rounded to the nearest tenth

3 0

3 years ago

Read 2 more answers

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

2 years ago