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3 years ago

On 34 acres of land there are total of 8942 trees. If spread evenly how many trees are on each acre?

Mathematics

2 answers:

fenix001 [56]3 years ago

6 0

You divide 8942 by 34
8942/34
This equals 263

goldenfox [79]3 years ago

3 0

263 trees on each acre

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Whilst shopping, the probability that Caroline buys fruit is 0.4. The probability that Caroline independently buys a CD is 0.2.

AleksandrR [38]

Answer:

probability that Caroline buy both CD and fruit = 0.52

Step-by-step explanation:

We have given that the probability of Caroline buys a fruit P = 0.4

So probability of Caroline does not buy the fruit = 1 - 0.4 = 0.6

Probability Caroline buys a CD P = 0.2

So probability of Caroline does not buy the CD = 1 - 0.2 = 0.8

So probability that Caroline does not buy either buy CD or fruit = 0.8×0.6=0.48

So probability that Caroline buy both CD and fruit =1-0.48 = 0.52

7 0

3 years ago

a farmer sold 2/5 of his cows and another 10th was stolen he then gave 20% of the cows that was left what percentage of the cows

igor_vitrenko [27]

Answer:

4/5 of the cattle is left

Step-by-step explanation:

Given,

A farmer sells 2/5 of his cattle

Let "x" be the total number of cattle

Then,

sold = 2 / 5 x

Then,

Remaining = x - 2x / 5

remaining = 3x / 5

He gives 1/3 of the remainder to his son

son = 1 / 3 × 3x / 5

son = x / 5

Then,

Remaining = 3x / 5 - x / 5

Remaining = 4x / 5

Hope this answer helps you :)

Have a great day

Mark brainliest

Thus 4/5 of the cattle is left

8 0

3 years ago

What if a fence painting competition allowed pairs to compete? If Ben Rogers can paint the fence in 8 min on his own and Johnny

Delvig [45]

Answer:

I'm confused on what it's asking

Step-by-step explanation:

7 0

3 years ago

The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1

evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\$

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

$\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07$

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193$

The 98% confidence interval for the population mean is (2146, 2193).

3 0

3 years ago

You walk 2 miles in 12

uranmaximum [27]

2m = 25/2
m= 25/2 divided by 2
m= 25/4
3m= 25/4 x 3
3m= 75/4
so she does 3 miles in 18 3/4 hours

3 0

3 years ago

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