<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
The relationship in this equation is linear, but not proportional. If it was proportional, then replacing x with nx should give ny as the answer. Example:
y = 3x
Replace x with 2x.
y' = 3(2x) = 2(3x) = 2y
y' = 2y
This is proportional. But if you replace x with 2x in
y = 3x + 5,
you will not get 2y for y'. This case is not proportiona
Answer:
642000000000000000000000
Step-by-step explanation:
Answer:
25% decrease
Step-by-step explanation:
First find the amount of decrease ( we know this is a decrease since it got smaller)
24-18) =6
Take this over the original amount
6/24 = 1/4 = .25
Change to percent form
25%
25% decrease
