So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
The answer would be C because it’s the only fraction that does not equal 0.4
See attachment for one such shell. The volume is given by the sum of infinitely many thin shells like this, each with radius
and height determined by the vertical distance between the upper blue curve and the lower orange curve for any given
, i.e.
.
The volume is then
Answer:
y = 39
Step-by-step explanation:
550 x 
= 
x 11 + y
550 x 
= x 11 x 11 + y
550 x x 
= 11 x 11 + y
550 = 11 x 11 + y
= 
x 11 + y
50 = 11 + y
50 - 11 = y
39 = y
Answer: A
I used my graphic calculator
