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zysi [14]
3 years ago
8

Please help lol thankss

Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

what's your question though?

WINSTONCH [101]3 years ago
5 0
What’s the question lol
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A standard deck of cards has 52 cards, 4 of each type (Ace, King, Queen, Jack, 10,...,2). From a well-shuffled deck, you are dea
Wewaii [24]

Answer:

a)%85,5

b)%92,2

Step-by-step explanation:

a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.

(36/52)*(35/51)*(34/50)*(33/49)*(32/48)=0,145

Then, we need to deduct this value from the probability 1

1-0,145=0,855

The probability of the hand with at least one face is %85,5.

b)To determine the probability of a hand with at least one ace and face we will track the same road again.

(32/52)*(31/51)*(30/50)*(29/49)*(28/48)=0,0775

Then, we need to deduct this value from the probability 1

1-0,0775=0,922

The probability of the hand with at least one ace and one face is %92,2.

3 0
3 years ago
Which ratios form a proportion?
ElenaW [278]
Your answer would be D.

This is because you could multiply 5/8 by 2 to get 10/16.
5 0
4 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!
Vadim26 [7]

Answer:

one on the left is p=139. one on the right is p=117 I believe this is the right answers if not then I'm sorry

8 0
3 years ago
Let v=-9i+j and w=-i-6j find 8v-6w
hram777 [196]

Answer:

78i+52j

Step-by-step explanation:

8(9i+2j)-6(-i-6j)

72i+16j+6i+36j

=78i+52j

7 0
3 years ago
Two fish tanks have measurements as shown.
I am Lyosha [343]

Step-by-step explanation:

sgshshsbhehdbdbdbsbehebebdbebd

4 0
2 years ago
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