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serious [3.7K]
3 years ago
12

What is the equation of a line that passes through the points (3,6) and (8, 4)?

Mathematics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.  

First, you should find the slope of the line.  To do this, use the equation M=y2-y1/x2-x1.  Using the two given points (3,6) and (8,4), you can solve for M.  

M=4-6/8-3

M=-2/5 (-0.4 in decimal form)

Now, your equation is y=-0.4x+b

Next you must solve for b to find the y-intercept.  You can do this by subbing one of the given points in for x and y.  

Using the point (3,6):

y=-0.4x+b

6=-0.4(3)+b

6=-1.2+b

Isolate b:

6+1.2=b

b=7.2

And now you have the equation of the line!

y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)

Step-by-step explanation:

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Help me plz and show work <3
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Answer:

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Step-by-step explanation:

here's your solution

=> 7y + 2x = 5

=> 7y = 5 - 2x

=> y = (5-2x)/7

\huge\mathfrak\red{hope \: it \: helps...}

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