Which is greater 2/3 or 2/4

Find the point-slope form of the line with the given slope which passes through the indicated slope. Slope = - 8/9 line passes t

kiruha [24]

Y - 8 =(-8/9)(x - 3)

y - 24/3 = (-8/9)x + 8/3

y = (-8/9)x + 32/3

6 0

3 years ago

Read 2 more answers

After the booster club sold 40 hotdogs at a football game, it had 90$ in profit. After the next game, it had sold a total of 80

sergiy2304 [10]

Let's first establish what we already know for this problem.

x = total number of hotdogs sold
y = total profit from total sales of hotdogs

Let's also establish the other equations which we will require in order to solve this problem.

Equation No. 1 -
Profit for 40 hotdogs = $90 profit

Equation No. 2 -
Profit for 80 hotdogs = $210 profit

STEP-BY-STEP SOLUTION

From this, we can use the formula y = mx + b & substitute the values for x & y from one of the two previous equations into the formula in order to obtain the values of m & b for the final equation. Here is an example of the working out as displayed below:

Firstly, using the first or second equation, we make either m or b the subject. Here I have used the first equation and made m the subject:

Equation No. 1 -
y = mx + b
90 = m ( 40 ) + b
40m = 90 - b
m = ( 90 - b ) / 40

Now, make b the subject in the second equation as displayed below:

Equation No. 2 -
y = mx + b
210 = m ( 80 ) + b
210 = 80m + b
b = 210 - 80m

Then, substitute m from the first equation into the second equation.

Equation No. 2 -
b = 210 - 80m
b = 210 - 80 [ ( 90 - b ) / 40 ]
b = 210 - [ 80 ( 90 - b ) / 40 ]
b = 210 - 2 ( 90 - b )
b = 210 - 180 - 2b
b - 2b = 30
- b = 30
b = - 30

Now, substitute b from the second equation into the first equation.

Equation No. 1 -
m = ( 90 - b ) / 40
m = ( 90 - ( - 30 ) / 40
m = ( 90 + 30 ) / 40
m = 120 / 40
m = 3

Through this, we have established that:

m = 3
b = - 30

Therefore, the final equation to model the final profit, y, based on the number of hotdogs sold, x, is as follows:

y = mx + b
y = ( 3 )x + ( - 30 )

ANSWER:
y = 3x - 30

3 0

3 years ago

The distance between the points (4, 5) and (2, 2)

Morgarella [4.7K]

Answer:

(2,3)

Step-by-step explanation:

6 0

3 years ago

Jacob purchased a bag of 60 marbles of various colors. The bag contained 20 red, 15 green and 25 blue marbles. What percent of t

zalisa [80]

<h3>Answer: 25%</h3>

Work Shown:

15 green out of 60 total

15/60 = 1/4 = 0.25 = 25%

5 0

3 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

3 years ago