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3 years ago

Please I need help, if you could show work too that would be amazing

Mathematics

1 answer:

Ainat [17]3 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

Hi there,

We know that the value of ∠ABD and ∠DBC are the same because BD bisects it. Therefore, we can set both of the angle values equal to each other to find the value of x.

9x = (8x + 3)

x = 3

Hope this answer helps. Feel free to ask questions. Cheers.

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Drag the correct steps into order to evaluate 42 + t6 for t = 12.

faltersainse [42]

Answer:

42+ (12)6=

42+72=114

Step-by-step explanation:

use pemdas to eliminate parethesis then add them together

7 0

3 years ago

Which polynomials are prime? Check all that apply.

insens350 [35]

15x2+10x-9x+7
8x3+20x2+3x+12
11x4+4x2-6x2-16
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8 0

3 years ago

Read 2 more answers

Find the inverse Laplace transforms, as a function of x, of the following functions:

inn [45]

Answer: The required answer is

$f(x)=e^x+\cos x+\sin x.$

Step-by-step explanation: We are given to find the inverse Laplace transform of the following function as a function of x :

$F(s)=\dfrac{2s^2}{(s-1)(s^2+1)}.$

We will be using the following formulas of inverse Laplace transform :

$(i)~L^{-1}\{\dfrac{1}{s-a}\}=e^{ax},\\\\\\(ii)~L^{-1}\{\dfrac{s}{s^2+a^2}\}=\cos ax,\\\\\\(iii)~L^{-1}\{\dfrac{1}{s^2+a^2}\}=\dfrac{1}{a}\sin ax.$

By partial fractions, we have

$\dfrac{s^2}{(s-1)(s^2+1)}=\dfrac{A}{s-1}+\dfrac{Bs+C}{s^2+1},$

where A, B and C are constants.

Multiplying both sides of the above equation by the denominator of the left hand side, we get

$2s^2=A(s^2+1)+(Bs+C)(s-1).$

If s = 1, we get

$2\times 1=A(1+1)\\\\\Rightarrow A=1.$

Also,

$2s^2=A(s^2+1)+(Bs^2-Bs+Cs-C)\\\\\Rightarrow 2s^2=(A+B)s^2+(-B+C)s+(A-C).$

Comparing the coefficients of x² and 1, we get

$A+B=2\\\\\Rightarrow B=2-1=1,\\\\\\A-C=0\\\\\Rightarrow C=A=1.$

So, we can write

$\dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s+1}{s^2+1}\\\\\\\Rightarrow \dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}.$

Taking inverse Laplace transform on both sides of the above, we get

$L^{-1}\{\dfrac{2s^2}{(s-1)(s^2+1)}\}=L^{-1}\{\dfrac{1}{s-1}\}+L^{-1}\{\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}\}\\\\\\\Rightarrow f(x)=e^{1\times x}+\cos (1\times x)+\dfrac{1}{1}\sin(1\times x)\\\\\\\Rightarrow f(x)=e^x+\cos x+\sin x.$

Thus, the required answer is

$f(x)=e^x+\cos x+\sin x.$

4 0

4 years ago

a rectangular wall with a length of 10x and width of 20 x has a rectangular doorway with a length of 5x and a width of 2x. What

Shtirlitz [24]

Answer:

∴ The the surface area of the wall is $190x^{2} \ square\ unit$ .

Step-by-step explanation:

Given that,

The length of rectangular wall is $10x$ .

The width of rectangular wall is $20x.$

The length of doorway is $5x.$

The width of doorway is $2x.$

and, we have to find the surface area of rectangular wall.

Now,

The length of rectangular wall is $10x$ .

The width of rectangular wall is $20x.$

∴ Total surface area of a rectangular wall $= Length\ of\ wall\times Width\ of\ wall$

$= 10x\times 20x$

$=$ $200x^{2} \ square\ unit$

Total surface area of a rectangular wall is $200x^{2} \ square\ unit$ .

Again, The length of doorway is $5x.$

The width of doorway is $2x.$

∴Total surface area of doorway $=Lenght\ of\ doorway\times Width\ of\ doorway$

$=5x\times 2x$

$=10x^{2} \ square\ unit$

Total surface area of doorway is $10x^{2} \ square\ unit$ .

∴The remaining surface area of a rectangular wall is $=$ $200x^{2} -10x^{2}$

$=190x^{2} \ square\ unit$

∴ The the surface area of the wall is $190x^{2} \ square\ unit$ .

6 0

4 years ago

Which is not a part or budget?

8_murik_8 [283]

Answer:

I think D.

Step-by-step explanation:

Depending on the feasibility of these estimates, Budgets are of three types -- balanced budget, surplus budget and deficit budget. Depending on the feasibility of these estimates, budgets are of three types -- balanced budget, surplus budget and deficit budget.

7 0

3 years ago