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3 years ago

Please I need help, if you could show work too that would be amazing

Mathematics

1 answer:

Ainat [17]3 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

Hi there,

We know that the value of ∠ABD and ∠DBC are the same because BD bisects it. Therefore, we can set both of the angle values equal to each other to find the value of x.

9x = (8x + 3)

x = 3

Hope this answer helps. Feel free to ask questions. Cheers.

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Given the function f(x) = The quantity of 2x minus 5, divided by 3 , which of the below expressions is correct? (1 point) f−1(x)

Anuta_ua [19.1K]

Answer:

$f^{-1}(x)$ =the quantity of 3x plus 5 divided by 2

Step-by-step explanation:

We are given that a function $f(x)=\frac{2x-5}{3}$

We have to find the correct expression

Suppose y= $\frac{2x-5}{3}$

$3y=2x-5$

$3y+5=2x$

$x=\frac{3y+5}{2}$

Therefore, $f^{-1}(x)=\frac{3x+5}{2}$

Answer: $f^{-1}(x)$ =the quantity of 3x plus 5 divided by 2

8 0

3 years ago

Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$

= $\frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}$

= $\frac{2}{1} +\frac{2}{1}$

= 4

3 0

3 years ago

Please help, Thankyou

slega [8]

$\text {Mass of earth =} 5.97 \times 10^{24} \text { kg}$

$\text {Mass of Venus =} 4.87 \times 10^{24} \text { kg}$

$\text {Difference = }5.97 \times 10^{24} - 4.87 \times 10^{24}$

$\text {Difference = }(5.97 - 4.87) \times 10^{24}$

$\text {Difference = }1.1 \times 10^{24} \text { kg}$

--------------- In Pure Text Format --------------
Mass of the earth = 5.97 x 10^{24}
Mass of Venus = 4.87 x 10^{24}
Difference = (5.97 - 4.87) x 10^{24} = 1.1 x 10^{24} kg

4 0

3 years ago

30 POINTS !!!

antoniya [11.8K]

Maybe 40? i hope this helps

3 0

3 years ago

Read 2 more answers

Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply. A. 400 • 0.32 B. 4

irina1246 [14]

Answer: Option 'C' is correct.

Step-by-step explanation: