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2 years ago

Suppose that a polynomial function of degree 5 with real coefficients has 4, -3i, and 9- 2i as zeros. Find the remaining zeros.

Mathematics

1 answer:

Naya [18.7K]2 years ago

6 0

9514 1404 393

Answer:

3i, 9+2i

Step-by-step explanation:

Polynomials with real coefficients have complex zeros in conjugate pairs. The conjugates of the given complex zeros are the ones that are remaining:

3i and 9+2i

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Step-by-step explanation:

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Answer:

(-6, 0)

Step-by-step explanation:

y = 4x + 24

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2 years ago

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(84x - 69y) - (65x + 34y)

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(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

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