Suppose that a polynomial function of degree 5 with real coefficients has 4, -3i, and 9- 2i as zeros. Find the remaining zeros.
1 answer:
9514 1404 393
Answer:
3i, 9+2i
Step-by-step explanation:
Polynomials with real coefficients have complex zeros in conjugate pairs. The conjugates of the given complex zeros are the ones that are remaining:
3i and 9+2i
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