9514 1404 393
Answer:
3i, 9+2i
Step-by-step explanation:
Polynomials with real coefficients have complex zeros in conjugate pairs. The conjugates of the given complex zeros are the ones that are remaining:
3i and 9+2i
5
Number 4 would be: C
And number 5 would be: C
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Answer:5
w(n)=4-1
=5