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3 years ago

Brainliest for best answer

Mathematics

1 answer:

pickupchik [31]3 years ago

7 0

Answer:

1. 120, 2. 6, 3. 21

Step-by-step explanation:

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Choose Yes or No to tell whether the Addition Property of Inequality can be used to solve each statement. w – 4 > –10 12 ≥ 20

Alex

Answer:

Step-by-step explanation:

The inequality will not be the same if the same amount is added both sides.

The addition property states that if the same quantity is added to both sides, then the inequality still remains true. Take for example:

let x, y, and z be real numbers. It follows that:

if x ≥ y, then x + z ≥ y + z

This holds true for whatever value of z

If x ≤ y, then x + z ≤ y + z

The inequality remains true.

4 0

3 years ago

A pair of Jean's that normally sells for 35$ is on sale for 20% off .Find the sale price of the Jean's. then find the total cost

Oksi-84 [34.3K]

Answer:

Sale price $28 With tax $26.32 ez

Step-by-step explanation:

4 0

3 years ago

Whats the Prime Factorization of 28?

andrew-mc [135]

We have that the prime factorization is 28 = 2x2x7.

8 0

1 year ago

2/3 of 1 is<br> What is this

andrezito [222]

2/3 of 1 is simply 2/3 or 0.667

6 0

3 years ago

40 points and brainliest to the best correct answer, questions in photo.

vodomira [7]

Answer:

2. w = -3

4. c = -2

6. r = 7

8. n = 4

Step-by-step explanation:

It's hard to read the photo, but I'll try.

$2^{w + 4} \times 2^{4w + 6} = 2^{2w + 1}$

On the left side, you have a product of 2 powers with the same base.

Give the same base and add the exponents, as in the rule

$a^m \times a^n = a^{m + n}$

You get on the left side 2 to the sum of the exponents.

$2^{w + 4 + 4w + 6} = 2^{2w + 1}$

Simplify the long exponent on the left side.

$2^{5w + 10} = 2^{2w + 1}$

Now we have another rule we can use. If two powers are equal, and their bases are equal, then the exponents must be equal.

Here, 2 to the power 5w + 10 equals 2 to the power 2w + 1. Since both bases are 2 and are equal, then the exponents must be equal.

5w + 10 = 2w + 1

Subtract 2w from both sides. Subtract 10 from both sides.

3w = -9

Divide both sides by 3.

w = -3

$\dfrac{1}{5} = 5^{2c + 3}$

We need to write the left side as a power of 5. Then we equate the exponents like we did in problem 2.

Recall the rule:

$a^{-n} = \dfrac{1}{n}$

Apply this rule to the left side in reverse.

$5^{-1} = 5^{2c + 3}$

Now we have two powers that are equal, both having the same base, 5, so the exponents must be equal.

2c + 3 = -1

2c = -4

c = -2

$216 = 6^{2r - 11}$

This is the same idea as problem 4. Write the left side as a power of 6.

$6^3 = 6^{2r - 11}$

$2r - 11 = 3$

$2r = 14$

$r = 7$

r = 7

$4^{n} \times 4^{2n - 9} = 64$

This problem is similar to problem 2.

$4^{n + 2n - 9} = 4^3$

$4^{3n - 9} = 4^3$

3n - 9 = 3

3n = 12

n = 4

4 0

2 years ago