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Sliva [168]
2 years ago
14

Can someone help me pls!!

Mathematics
2 answers:
nordsb [41]2 years ago
7 0

Answer:

a=1

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite sides of a parallelogram are equal.

Therefore, set any two opposite sides equal to each other to solve for a:

a+3=2a+2,\\\\3=a+2,\\a=\boxed{1}

Yuri [45]2 years ago
7 0

Answer:

a+3 = 2a+2

a+6 = 6a+1

-------------

a = -1

5a = -5

a = -1

a = -1

You might be interested in
The longest side of a triangle is 4 more than twice the shortest. The third side is 3 more than the shortest. The perimeter is 3
kondaur [170]

Answer:

The shortest side = 6

The third side = 9

The hypotenuse (the longest side) = 16

Step-by-step explanation:

First, let's establish the following based on the information given:

The shortest side = x

The third side = (x + 3)

The hypotenuse (the longest side) = (2x + 4)

The perimeter = 31

Since the perimeter is the total of all 3 sides, we are left with this equation:

(x) + (x + 3) + (2x + 4) = 31

From here, combine like-terms and solve for x.

(x) + (x + 3) + (2x + 4) = 31

(4x + 7) = 31

4x = 24

x = 6

Now that we know the value of x, we can apply this to the predetermined formulas to find the measurements of the remaining two sides.

The shortest side = 6

The third side = (x + 3) = 9

The hypotenuse (the longest side) = (2x + 4) = (2(6) + 4) = (12 + 4) = 16

To check, add all of the sides together to make sure they equal 31.

6 + 9 + 16 = 31

~Hope this Helps!~

7 0
2 years ago
What method most efficient to use to solve x^2+4x+3=0
Alik [6]
My recommendation would be to factor..
x² + 4x + 3 = 0 factor the left side into two binomials
(x + 3)(x + 1) = 0 set each of these binomials equal to zero and solve

x + 3 = 0 Implies x = -3
x + 1 = 0 implies x = -1
6 0
3 years ago
1. write it on a piece of paper
stiv31 [10]

\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}

\\ \sf\longmapsto \dfrac{6+11}{4}

\\ \sf\longmapsto \dfrac{17}{4}

2:-

\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}

\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}

\\ \sf\longmapsto \dfrac{155+225}{35}

\\ \sf\longmapsto \dfrac{380}{35}

\\ \sf\longmapsto 12

3:-

\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}

\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}

\\ \sf\longmapsto \dfrac{132+160}{30}

\\ \sf\longmapsto \dfrac{292}{30}

4:-

\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}

\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}

\\ \sf\longmapsto 4+\dfrac{10}{3}

\\ \sf\longmapsto \dfrac{12+10}{3}

\\ \sf\longmapsto \dfrac{22}{3}

7 0
3 years ago
Read 2 more answers
The volume of a box can be found by multiplying the length times width times height of a box (v=lwh). If the volume of a box is
Andrej [43]

Answer:

  about 10.924 inches

Step-by-step explanation:

If all of the dimensions are equal, the box is a cube. Its side length is the cube root of the volume.

  V = s³

  s = ∛V = ∛1300 ≈ 10.913929 . . . . inches

8 0
3 years ago
Read 2 more answers
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
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