To get this it helps to know the electronegativity numbers of the elements but it isn't required. You just need to know that Fluorine is the most electronegative element and that the farther away from Fluorine you are on the periodic table, the less electronegative you get. The one exception to this rule is hydrogen with actually has an electronegativity of 2.1 while lithium has one of 1.0. Also the higher difference in electronegativity between two atoms the more polar the bond is.
Now to start the question. H-Br could be a contender since H has an electronegativity number of 2.1 and Br is relatively close to Fluorine so we'll put that one aside for now. H-Cl knocks out A because both bonds have H but one bond has Br and the other has Cl. Cl is closer to Fluorine than Br so answer B is the contender now. For answer C, I and Br are too close to have a higher electronegativity difference than H-Cl so that one isn't it. Finally for answer D, I is much closer to Cl than H is so the electronegativity difference is much less, making your answer B.
Explanation:
there are 8 atoms of hydrogen
Complete Question
The complete question is shown on the first uploaded image
Answer:
The bond angle is 104.48⁰
Explanation:
The explanation is shown on the second uploaded image
Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.
<h3>Meaning of Semiconductors</h3>
Semiconductors can be defined as any material that has the ability to exhibit some properties of a conductor and some properties of an insulator.
A semiconductor can be used as either a conductor or an insulator when worked upon.
In conclusion, Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.
Learn more about semiconductors: brainly.com/question/1918629
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