Answer:
B.
Explanation:
Some of the elements of the third-period and periods below can have expanded octet because they have d- sub-level.
We have 2 possible answers. A and B. Because lodine and chlorine. Sulfur and phosphorous are in the 3d or lower periods.
In the compound P2S5, where P forms 5 bonds.
Iodine and chlorine do not have enough difference in electronegativity to form compound ICl7.
So, the answer is B.
Answer:
[H+] is 3.31 × 10^-11 M
Solution: Basic
Explanation:
In the question we are given;
Concentration of Hydroxide ion [OH-] as 3.0 × 10^-4 M
We are required to determine the [H+] and whether the solution is acidic, basic or neutral.
We know that;
pOH + pH = 14
and that;
pOH = - log [OH-]
Therefore;
pOH = - log ( 3.0 × 10^-4)
= 3.52
But;
pH = 14 - pOH
Thus;
pH = 14 - 3.52
= 10.48
But, we know that;
pH = - log[H+]
Therefore;
H+ = Antilog -pH
= Antilog -10.48
= 3.31 × 10^-11
Thus, the concentration of H+ ions [H+] is 3.31 × 10^-11 M
Also since the pH is 10.48, then the solution is basic
N=1.2·10²⁴
Nₐ=6.0221·10²³ mol⁻¹
n₂(H₂O)=4 mol
n₁(H₂O)=N/Nₐ
n=n₁+n₂=N/Nₐ+n₂
n=1.2·10²⁴/6.0221·10²³ + 4 = 5.99 mol
5.99 <span>moles of water are in the glass</span>
Answer:
A big bang occurred in the solar system as a resultof a fusion reaction.All matter I the solar system had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies the solar system were formed
Answer:
97 000 g Na
Explanation:
The absortion (or liberation) of energy in form of heat is expressed by:
q=m*Cp*ΔT
The information we have:
q=1.30MJ= 1.30*10^6 J
ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)
Cp=30.8 J/(K mol Na)
If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.
To do so, we use the molar mass of Na= 22.99g/mol
Now, we are able to solve for m:
=97 000 g Na
