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3 years ago

5

Question 12solid sodium and chlorine gas combine to form solid sodium chloride .write a balanced chemical equation for this reac

tion.

1 answer:

MrRa [10]3 years ago

6 0

2Na(s) + Cl₂(g) ---> 2 NaCl(s)
:)

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A 5.00g quantity of a diprotic acid was dissolved in water and made up exactly 250 mL. Calculate the molar mass if the acid is 2

MAXImum [283]

Answer:

The molar mass of the diprotic acid is 90.10 g/mol.

Explanation:

The acid is 25.0 mL of this solution required 11.1 mL of 1.00 KOH for neutralization.

$H_2A+2KOH\rightarrow K_2A+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$ ( neutralization )

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of diprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=2\\M_1=?\\V_1=25 mL\\n_2=1\\M_2=1.00 M\\V_2=11.1 mL$

Putting values in above equation, we get:

$2\times M_1\times 25=1\times 1.00\times 11.1}$

$M_1=\frac{1\times 1.00\times 11.1}{2\times 25}=0.222 M$

Molarity of acid solution = 0.222 M =0.222 mol/L

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Moles of diprotic acid in 0.250 L solution :

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Mass of diprotic acid = m = 5.00 g

$Moles(n)=\frac{mass(m)}{\text{Molar mass(M)}}$

$M=\frac{m}{n}=\frac{5.00 g}{0.0555 mol}=90.10 g/mol$

The molar mass of the diprotic acid is 90.10 g/mol.

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