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3 years ago

Please help me answer this engineering question

Engineering

1 answer:

wel3 years ago

3 0

Https://www.bartleby.com/solution-answer/chapter-26-problem-5sq-electric-motor-control-10th-edition/9781133702818/what-is-meant-by-the-low-or-poor-starting-economy-of-a-primary-resistor-starter/fb257667-8e6f-11e9-8385-02ee952b546e this website has 26 solutions maybe this will help

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Need help with these 3 questions pls help

Anton [14]

Answer:

I think 5 is passion and 6 is true I think and 7 is time management I'm pretty sure

3 0

3 years ago

Molten metal is poured into the pouring cup of a sand mold at a steady rate of 400 cm3/s. The molten metal overflows the pouring

umka2103 [35]

Answer:

the proper diameter at its base so as to maintain the same volume flow rate is 1.6034 cm

Explanation:

Given the data in the question ;

flowrate Q = 400 cm³/s

cross section of the sprue is round

Diameter of sprue at the top d_top = 3.4 cm

Height of sprue = 20 cm = 0.2 m³

the proper diameter at its base so as to maintain the same volume flow rate = ?

first we determine the velocity at the sprue base

V_base = √2gh = √( 2×9.81×0.2) = √3.924 = 1.980908 m = 198.0908 cm

so, diameter of the sprue at the bottom will be

Q = AV = [ (( πd²_bottom)/4) × V_bottom ]

d_bottom = √(4Q/πV_bottom)

we substitute

d_bottom = √((4×400)/(π×198.0908 ))

d_bottom = √( 1600/622.3206)

d_bottom = √2.571022

d_bottom = 1.6034 cm

Therefore, the proper diameter at its base so as to maintain the same volume flow rate is 1.6034 cm

8 0

3 years ago

How many volts of electricity would it take to power up an entire city? Take Tokyo for example. Please explain!

jek_recluse [69]

Answer:

maybe a couple million volts

Explanation:

because there are outlets you need to charge your phone maybe you car if you have a tesla and skyscrapers

3 0

3 years ago

Compute the area and circumference of a circle given the radius r if the radius is greater than or equal to 1.0; otherwise, you

Maslowich

In this question we shall present the algorithm in pseudocode, whose structure is now summarized:

1) Inputs.

2) Algorithms.

3) Outputs.

Please notice that While-cycles consider the requirement of using the algorithm as many times as user wants.

Name: Area-or-Circunference

CHAR - decide

REAL - radius, circumference, area

Say "Do you want to calculate? [Y] - Yes/[N] - No";

Write decide;

While (decide != 'Y' and decide != 'y' and decide != 'N' and decide != 'n'):

Say "Invalid option. Do you want to calculate? [Y] - Yes/[N] - No";

Write decide;

end-While

While (decide = 'Y' or decide = 'y'):

Say "Please indicate a radius";

While (radius < 0):

Say "Radius must be equal or greater than 0. Please indicate a

radius";

Write radius;

end-While

If (radius < 1):

circumference = 2*3.14*radius;

Say "The circumference has a value of %circumference length units";

Else:

circumference = 2*3.14*radius;

area = 3.14*radius*radius;

Say "The circumference has a value of %circumference length units

and the area has a value of %area square units";

end-If

Say "Do you want to calculate? [Y] - Yes/[N] - No";

Write decide;

While (decide != 'Y' and decide != 'y' and decide != 'N' and decide !=

'n'):

Say "Invalid option. Do you want to calculate? [Y] - Yes/[N] - No";

Write decide;

end-While

If (decide = 'N' or decide = 'n'):

Say "Good luck";

end-If

We kindly invite to see this question on algorithms: brainly.com/question/17780739

6 0

2 years ago

An experiment compares the initial speed of bullets fired from two handguns: a 9 mm and a 0.44 caliber. The guns are fired into

olasank [31]

Answer:

1.176

Explanation:

When the bullets impact the mass they become embedded on it, it is a plastic collision, therefore momentum is conserved.

v2 * (M + mb) = v1 * mb

Where

v1: muzzle velocity of the bullet

M: mass of the bob

mb: mass of the bullet

v2: mass of the bob with the bullet after being hit

v2 = v1 * mb / (M + mb)

Upon being impacted the bob will acquire speed v2, this implies a kinetic energy. The bob will then move and raise a height h. Upon acheiving the maximum height it will have a speed of zero. At that point all kinetic energy will be converted into potential energy.

Ek = 1/2 (M + mb) * v2^2

Ep = (M + mb) * g * h

Ek = Ep

1/2 (M + mb) * v2^2 = (M + mb) * g * h

1/2 * (v1 * mb / (M + mb))^2 = g * h

1/2 * v1^2 * mb^2 / (M + mb)^2 = g * h

v1^2 = g *h * (M+ mb)^2 / (1/2 * mb^2)

$v2 = \sqrt{\frac{g *h * (M+ mb)^2}{\frac{1}{2} * mb^2}}$

The height h that it reaches is related to the length L of the pendulum arm and the angle it forms with the vertical.

h = L * (1 - cos(a))

$v2 = \sqrt{\frac{g * L * (1 - cos(a)) * (M+ mb)^2}{\frac{1}{2} * mb^2}}$

For the 9 mm:

$v2 = \sqrt{\frac{9.81 * L * (1 - cos(4.3)) * (10+ 0.006)^2}{\frac{1}{2} * 0.006^2}} = \sqrt{L} * 391$

For the 0.44 caliber:

$v2 = \sqrt{\frac{9.81 * L * (1 - cos(10.1)) * (10+ 0.012)^2}{\frac{1}{2} * 0.012^2}} = \sqrt{L} * 460$

The ratio is 460 / 391 = 1.176

6 0

3 years ago