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irina1246 [14]
3 years ago
12

Need help with these 3 questions pls help

Engineering
1 answer:
Anton [14]3 years ago
3 0

Answer:

I think 5 is passion and 6 is true I think and 7 is time management I'm pretty sure

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A particle is moving along a straight line with an initial velocity of 6 m/s when it is subjected to a deceleration of a- (-1.5v
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a=-1.5v^\frac{1}{2}\\v\frac{\mathrm{d} v}{\mathrm{d} s}=-1.5v^\frac{1}{2}\\-1.5ds=v^\frac{1}{2}dv\\\int\ {-1.5} \, ds= \int\ v^\frac{1}{2}dv\\-1.5s=\frac{2}{3}\times v^{\frac{3}{2} }

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now for time calculation we know that

a=\frac{\mathrm{d}v }{\mathrm{d} t}

-1.5v^\frac{1}{2} =\frac{\mathrm{d}v }{\mathrm{d} t}\\-1.5dt=\frac{dv}{v^\frac{1}{2}} \\\int -1.5 dt=\int v^{-\frac{1}{2}}dt \\1.5t=2v^\frac{1}{2}\\t=\frac{4}{3}v^\frac{1}{2}

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<u>I have given the explanation in the attached file below.</u>

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