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irina1246 [14]
3 years ago
12

Need help with these 3 questions pls help

Engineering
1 answer:
Anton [14]3 years ago
3 0

Answer:

I think 5 is passion and 6 is true I think and 7 is time management I'm pretty sure

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Write a function which multiplies the values in odd position values by 10. Odd positions in this case refers to the first value
xxMikexx [17]

Answer:

Using linkedlist on C++, we have the program below.

Explanation:

#include<iostream>

#include<cstdlib>

using namespace std;

//structure of linked list

struct linkedList

{

  int data;

  struct linkedList *next;

};

//print linked list

void printList(struct linkedList *head)

{

  linkedList *t=head;

 

  while(t!=NULL)

  {

      cout<<t->data;

      if(t->next!=NULL)

      cout<<" -> ";

     

      t=t->next;

  }

}

//insert newnode at head of linked List

struct linkedList* insert(struct linkedList *head,int data)

{

  linkedList *newnode=new linkedList;

  newnode->data=data;

  newnode->next=NULL;

 

  if(head==NULL)

  head=newnode;

  else

  {

      struct linkedList *temp=head;

      while(temp->next!=NULL)

      temp=temp->next;

     

      temp->next=newnode;

     

      }

  return head;

}

void multiplyOddPosition(struct linkedList *head)

{

  struct linkedList *temp=head;

  while(temp!=NULL)

  {

      temp->data = temp->data*10; //multiply values at odd position by 10

      temp = temp->next;

      //skip odd position values

      if(temp!= NULL)

      temp = temp->next;

  }

}

int main()

{

  int n,data;

  linkedList *head=NULL;

 

// create linked list

  head=insert(head,20);

  head=insert(head,5);

  head=insert(head,11);

  head=insert(head,17);

  head=insert(head,23);

  head=insert(head,12);

  head=insert(head,4);

  head=insert(head,21);    

 

  cout<<"\nLinked List : ";

  printList(head); //print list

 

  multiplyOddPosition(head);

  cout<<"\nLinked List After Multiply by 10 at odd position : ";

  printList(head); //print list

 

  return 0;

}

5 0
3 years ago
What Do Solar Engineers Do?
konstantin123 [22]
Plan, design, and implement solar energy projects
7 0
3 years ago
What is the next measurement after 2' -6" on the architect's scale?
Diano4ka-milaya [45]

Answer: I am not for sure

Explanation:

6 0
3 years ago
On some engines, after torquing cylinder head fasteners, you
djverab [1.8K]

Answer:

Re-torque the bolts as required while your engine is warm. But if you're using aluminum cylinder heads, you should wait until your engine is complete cooled until re-torquing

3 0
3 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
Aliun [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

5 0
3 years ago
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