The following displacement (cm), output (V) data have been recorded during a calibration of an LVDT. Displacement (cm), output (
V): 0.00 cm, 0.20 V; 0.125 cm, 0.60 V; 0.500 cm, 1.32 V; 0.769 cm, 1.95V; 1.019 cm; 2.33 V. Calculate the sensitivity of the LVDT expressed in (V/mm). (Please express your answer in V/mm and round up the answer to two (2) significant decimal digits.)
1 answer:
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Answer:
See explaination
Explanation:
Some of the Important Observation used in Entity Relational Diagram.
1. A Chemist can be involved one project or many projects
2. A project can hire just one or many chemists.
3. A chemist can lead over one or many projects
4. A project can have only one project leader chemist.
5. A project can be done in 1 or many laboratories.
6. A laboratory can host 0 or 1 projects.
7. A laboratory can have 1 or many equipments.
8. An Equipment can be in 1 or 0 laboratories.
9. A chemist can have 0 or many types of equipments.
10. An Equipment can have 0 or 1 chemist at a time
Notations:
PK=Primary Key:
A primary key, also called a primary keyword, is a key in a relational database that is unique for each record. It is a unique identifier, such as a driver license number, telephone number
FK=Foreign Key:
A foreign key is a column or group of columns in a relational database table that provides a link between data in two tables. It acts as a cross-reference between tables because it references the primary key of another table, thereby establishing a link between them
Composite key:
A composite key is a combination of two or more columns in a table that can be used to uniquely identify each row in the table when the columns are combined uniqueness is guaranteed, but when it is taken individually it does not guarantee uniqueness
Answer:
a. 9947 m
b. 99476 times
c. 2*10^11 molecules
Explanation:
a) To find the mean free path of the air molecules you use the following formula:
R: ideal gas constant = 8.3144 Pam^3/mol K
P: pressure = 1.5*10^{-6} Pa
T: temperature = 300K
N_A: Avogadros' constant = 2.022*10^{23}molecules/mol
d: diameter of the particle = 0.25nm=0.25*10^-9m
By replacing all these values you obtain:
b) If we assume that the molecule, at the average, is at the center of the chamber, the times the molecule will collide is:
c) By using the equation of the ideal gases you obtain: