Answer:
i believe it is 1625 newtons
Explanation:
I could be wrong but im assuming that it is 325 newtons per meter if not then the answer could be completely different
mark brainliest if you could
Answer:
a)Wt =25.68 lbf
b)Wt = 150 lbf
F= 899.59 N
Explanation:
Given that

m= 150 lbm
a)
Weight on the spring scale(Wt) = m g
We know that

Wt = 150 x 5.48/32 lbf
Wt =25.68 lbf
b)
On the beam scale
This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.
Wt = 150 lbf
If the plane is moving upward with acceleration 6 g's then the for F
F = m a
We know that


a=6 g's

So
F = 90 x 9.99 N
F= 899.59 N
Question:
The following tabulated data were gathered from a series of Charpy impact tests on a commercial low-carbon steel alloy.
Temperature(∘C)50403020100-10-20-30-40Impact energy (J)76767158382314951.5
(a) Plot the data as impact energy versus temperature.
(b) Determine a ductile-to-brittle transition temperature as the temperature corresponding to the average of the maximum and minimum impact energies.
(c) Determine a ductile-to-brittle transition temperature as the temperature at which the impact energy is 20 J.
Answer:
a) see the attached graph
b) max E = 76 and Min E =1.53 average = 77.5/2 = 38.75 J
this corresponds to about 10° C
c ) at E = 20 J temperature is about -2°C
Answer:
The correct option is;
C. A four-year pre-professional architecture degree
Explanation:
A student that already has a Pre-Professional four year degree such as a Bachelor of Arts (B.A.) or Bachelors of Science (B.S.) in architecture and has therefore, completed a certain amount of basic coursework related to architecture, whilst studying for their undergraduate degree can receive professional training/education by applying to a 2 year M.Arch. program whereby the combined bachelors and M.Arch program combined is known as a four-plus-two program
Answer:
heat transfer rate is -15.71 kW
Explanation:
given data
Initial pressure = 4 bar
Final pressure = 12 bar
volumetric flow rate = 4 m³ / min
work input to the compressor = 60 kJ per kg
solution
we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is
h1 = 262.96 kJ/kg
v1 = 0.05397 m³/kg
h2 = 310.24 kJ/kg
and here mass balance equation will be
m1 = m2
and mass flow equation is express as
m1 =
.......................1
m1 =
m1 = 1.2353 kg/s
and here energy balance equation is express as
0 = Qcv - Wcv + m × [ ( h1-h2) +
+ g (z1-z2) ] ....................2
so here Qcv will be
Qcv = m × [
] ......................3
put here value and we get
Qcv = 1.2353 × [ {-60}+ (310.24-262.96) ]
Qcv = -15.7130 kW
so here heat transfer rate is -15.71 kW