Whats 2+2+9+7+10+67+89+572+53+4=?
2 answers:
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Answer:
ii. 75 steps
iii. 75 steps
iv. 106 steps, and
Step-by-step explanation:
Let Musah's starting point be A, his waiting point after taking 50 steps northward and 25 steps westward be B, and his stopping point be C.
ii. From the second attachment, Musah's distance due west from A to C (AD) can be determined as;
bearing at B = , therefore <BCD =
To determine distance AB,
=
+
= 25000 + 625
= 3125
AB =
= 55.90
AB ≅ 56 steps
Thus, AC = 50 steps + 56 steps
= 106 steps
From ΔACD,
Sin =
⇒ x = 106 × Sin
= 74.9533
≅ 75 steps
Musah's distance west from centre to final point is 75 steps
iii. From the secon attachment, Musah's distance north, y, can be determined by;
Cos =
⇒ y = 106 × Cos
= 74.9533
≅ 75 steps
Musah's distance north from centre to final point is 75 steps.
iv. Musah's distance from centre to final point is AC = AB + BC
= 50 steps + 56 steps
= 106 steps
From ΔACD,
Tan θ =
= 1.0
θ = 1.0
=
Musah's bearing from centre to final point = +
=
and surely, you'd know how to get the values for the bounds there
Answer:
The angle Rick must kick the ball to score is an angle between the lines BX and BZY which is less than or equal to 32°
Step-by-step explanation:
The given measures of the of the angle formed by the tangent to the given circle at X and the secant passing through the circle at Z and Y are;
The direction Rick must kick the ball to score is therefore, between the lines BX and BXY
The angle between the lines BX and BXY = ∠XBZ = ∠XBY
The goal is an angle between
Let 'θ' represent the angle Rick must kick the ball to score
Therefore the angle Rick must kick the ball to score is an angle less than or equal to ∠XBZ = ∠XBY
By the Angle Outside the Circle Theorem, we have;
The angle formed outside the circle = (1/2) × The difference of the arcs intercepted by the tangent and the secant
We get;
∠XBZ = (1/2) × (122° - 58°) = 32°
The angle Rick must kick the ball to score, θ = ∠XBZ ≤ 32°