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almond37 [142]
4 years ago
7

Complete the table. Adults Children 8 1 16 2 24 A B 4

Mathematics
1 answer:
horrorfan [7]4 years ago
7 0
The answer is A = 3 and B = 32
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7
emmainna [20.7K]

It has a 0.6-mile-per-minute speed limit.

<h3>What is the distance?</h3>

Distance is defined as the product of speed and time.

Given that the distance traveled in 3 seconds is 3/100 miles.

To determine the distance it can travel in 1 minute.

We must first determine the distance traveled in 1 second in order to get the distance traveled in 1 minute.

It can cover 3/100 miles in 3 seconds.

So, in 1 second it can travel = 3/(100)(3) = 1/100 miles.

Now, We know that there are 60 seconds in a minute.

Thus, it can travel in a minute.

⇒ (1/100) × 60

⇒ 60/100

⇒ 6/10

⇒ 0.6 mile

Hence, It has a 0.6 mile per minute speed limit.

Learn more about distance here:

brainly.com/question/13269893

#SPJ1

8 0
2 years ago
Please answer this question​
Tems11 [23]

\bold{\huge{\underline{ Solution }}}

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

• \sf{ Polynomial :- ax^{2} + bx + c }

• The zeroes of the given polynomial are α and β .

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

Here, we have polynomial

\sf{ = ax^{2} + bx + c }

<u>We </u><u>know </u><u>that</u><u>, </u>

Sum of the zeroes of the quadratic polynomial

\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}

<u>And </u>

Product of zeroes

\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}

<u>Now, we have to find the polynomials having zeroes </u><u>:</u><u>-</u>

\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}

<u>T</u><u>h</u><u>erefore </u><u>,</u>

Sum of the zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}

\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}

\bold{{\dfrac{ -bc - ab}{ac}}}

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

<h3><u>Now</u><u>, </u></h3>

Product of zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}

\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}

\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The product of the zeroes are c/a + a/c + 2 .

<u>We </u><u>know </u><u>that</u><u>, </u>

<u>For </u><u>any </u><u>quadratic </u><u>equation</u>

\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }

\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3><u>Some </u><u>basic </u><u>information </u><u>:</u><u>-</u></h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0
2 years ago
triniti had $500 in a savings account at the beginning of the summer. She wants to have at least $200 in the account by the end
Citrus2011 [14]
500-(25x) < 200
Or it could be less than or equal too so the less than with a line under

3 0
4 years ago
Read 2 more answers
Examine the expanded form. A ∙ a ∙ a ∙ a ∙ a ∙ a ∙ a Which is the expression in exponential form? 7a 7a a7 a 7.
ICE Princess25 [194]
A^7. "A" raised to the power of 7 would be the exponential form. hope this helps.
7 0
3 years ago
An expression is shown. 590.92 - 219.38 What is the value of the expression?​
statuscvo [17]

371.54 is the answer :)

3 0
3 years ago
Read 2 more answers
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