Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Dr.hong prescribed the lest and Dr.evans prescribed the most. that is the answer but this is how i got the answer ok so you see that hong gave 0.019 that is not at all the same as 0.02 so you would add a zero to Evans so it would be 0.020 so it is the same length of hongs so now do you know how i got that if not then message me
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<em>A</em><em>+</em><em>2</em><em>2</em><em>°</em><em>=</em><em>9</em><em>0</em><em>°</em><em> </em><em>(</em><em>SUM</em><em> </em><em>OF</em><em> </em><em>COMPLEMENTRY</em><em> </em><em>ANGLES</em><em> </em><em>)</em>
<em>A</em><em>=</em><em>9</em><em>0</em><em>°</em><em>-</em><em>2</em><em>2</em><em>°</em>
<em>A</em><em>=</em><em>6</em><em>8</em><em>°</em><em> </em><em>ANSWER</em><em>.</em>
Answer:
1/4
Step-by-step explanation:
Both dice have odd numbers 1, 3, 5. The chances of getting an odd number on each number is 3/6
The probability of getting odd numbers on both is:
3/6 ⋅ 3/6 = 9/36 = 1/4
A: an exterior angle is supplementary to the adjacent interior angle.