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Aleksandr-060686 [28]
3 years ago
14

Sam is a forklift operator at a Los Angeles warehouse. A 500 kg crate arrived from Taiwan. His forklift can load 2,500 lb. He wa

nts to know if it is safe to lift the crate. How many pounds does the crate weigh?
PLZZZ HELP
Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

1 kg = 2.2 pounds ( rounded to the nearest tenth)

500 kg x 2.2 = 1,100 pounds

1100 pounds is less than 2,500 so the forklift can lift it.

Reptile [31]3 years ago
5 0

Answer:

2,500= 1133.981

Step-by-step

The answer is 1133.981 bc you would have to use the conversion rate of lb to kg, so just 2500 lb × 0.45359237

= 1133.980925 kg

0.45359237  this is the conversion rate therefore 1134 is the answer (was rounded)

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7 0
3 years ago
F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
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Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

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t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

4 0
3 years ago
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Answer:

True

Step-by-step explanation:

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