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Igoryamba
3 years ago
8

Based on the following rule for translations, how will the preimage translate to get the image? (x,y) = (x, y - 3) *​

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0
The preimage will be translated down by 3 units.
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brittany has a pack of 24 pencils, each pencil weighs 0.9 grams. how much does the pack of pencils weigh?
Sever21 [200]
The pack of pencils weighs 21.6 grams because 0.9 times 24 is 21.6 

7 0
3 years ago
Read 2 more answers
What is the value of the variable -38 = 2b + 25 - (-7b)
ddd [48]
The variable in this equation is b, therefore we have to calculate the value of b.

-38=2b+25-(-7b)
-38=2b+25+7b
2b+7b=-38-25
9b=-63
b=-63/9
b=-7

Answer: the value of the variable is b=-7

We can check it out this answer:
-38=2b+25-(-7b)
-38=2(-7)+25-(-7(-7))
-38=-14+25-49
-38=-38
4 0
3 years ago
Plzzzz help!!! I will give brainlist for the answer.
stira [4]

Answer: 34

Step-by-step explanation:

3 0
3 years ago
Please help !!<br>[90 points if correct]​
3241004551 [841]

Answer:

2201.8348 ; 3 ; x / (1 + 0.01)

Step-by-step explanation:

1)

Final amount (A) = 2400 ; rate (r) = 6% = 0.06, time, t = 1.5 years

Sum = principal = p

Using the relation :

A = p(1 + rt)

2400 = p(1 + 0.06(1.5))

2400 = p(1 + 0.09)

2400 = p(1.09)

p = 2400 / 1.09

p = 2201.8348

2.)

12000 amount to 15600 at 10% simple interest

A = p(1 + rt)

15600 = 12000(1 + 0.1t)

15600 = 12000 + 1200t

15600 - 12000 = 1200t

3600 = 1200t

t = 3600 / 1200

t = 3 years

3.)

A = p(1 + rt)

x = p(1 + x/100 * 1/x)

x = p(1 + x /100x)

x = p(1 + 1 / 100)

x = p(1 + 0.01)

x = p(1.01)

x / 1.01 = p

x / (1 + 0.01)

7 0
3 years ago
A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
4 years ago
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