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Lorico [155]
3 years ago
10

THANK YOU TO ANY ONE WHO ANSWERS QUESTIONS ON BRAINLY

Mathematics
2 answers:
Llana [10]3 years ago
7 0

Answer: Thx it feels good for people to encourage us.

Step-by-step explanation:

garri49 [273]3 years ago
6 0
I don’t see a question tho
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Simplify the following
irga5000 [103]

\huge\fbox{Answer ☘}

\bold\blue{( - 8z) {}^{2} } \\\bold{  =  > 64z {}^{2} }

hope helpful~

8 0
3 years ago
Plz help me really really fast this is my last question to work on
Artyom0805 [142]

Answer:

$5

Step-by-step explanation:

25 = 4e + 5

20 = 4e

5 = e

reach eraser costs $5.

6 0
3 years ago
Lucas and his three brothers opened a bag with 48 cookies there are 16 cookies left if each boy ate the same number of cookies h
FrozenT [24]

Answer:

each boy ate 8 cookies

Step-by-step explanation:

48-16=32

32 divided by 4=8

so each of them ate 8 cookies

5 0
3 years ago
A rubber ball is filmed as it bounces on a sidewalk at 25 frames every second. Predict how many seconds of film will be shown in
ANEK [815]
If for one second we have to reserve 25 frames to find length of the movie we have to divide 1750 by 25, so
1750:25=70 [seconds] - its the result

To better understand lets think that u have 8 piece of cake and u want to give every person 2 piece. To find how many person u can invite u can divide 8 by 2. The answer is 4 here ofc.
8 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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