Answer:
<u>Part A: </u>
<u>n = 5q (1st equation)</u>
<u>0.05n + 0.25q = 2 (2nd equation)</u>
<u>Part B:</u>
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
Step-by-step explanation:
Let's recall that a nickel has a value of $ 0.05 and a quarter a value of $ 0.25.
Let n represent the number of nickels and q represent the number of quarters.
Part A:
Write a system of equations to represent the situation.
n = 5q (1st equation)
n * 0.05 + q * 0.25 = 2
0.05n + 0.25q = 2 (2nd equation)
Part B:
Replacing n in the 2nd equation to solve for q:
0.05n + 0.25q = 2
0.05 * 5q + 0.25q = 2
0.25q + 0.25q = 2
0.5q = 2
q = 2/0.5
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
(3n+2)/(n-4) - (n-6)/(n+4)
common denominator (n-4)(n+4)
{(n+4)(3n+2)-(n-4)(n-6)}/{(n-4)(n+4)}
Use the foil method:
{(3n²+14n+8)-(n²-10n+24)}/{(n-4)(n+4)}
distribute negative sign:
{(3n²+14n+8-n²+10n-24)}/{(n-4)(n+4)}
subtract:
(2n²+24n-16)/{(n-4)(n+4)}
take out 2:
2{n²+12n-8}/{(n-4)(n+4)}
96,910. Is that what you were looking for?
Answer:
They can make 10 different groups of three.
Step-by-step explanation:
The order in which the people are in the car is not important, so we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many different groups of three can the five of them make?
Combinations of 3 from a set of 5. So
They can make 10 different groups of three.
