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3 years ago

Write an explicit formula for an, the nth term of the sequence 1, 11, 21

Mathematics

1 answer:

madreJ [45]3 years ago

5 0

Answer:

an = 10n - 9.

Step-by-step explanation:

This is arithmetic with first term a1 = 1 and common difference 10.

an = a1 + d(n-1)

= 1 + 10(n - 1)

= 1 + 10n - 10

= 10n - 9.

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Does - |-4| = | -(-4)?

Marta_Voda [28]

The first is an absolute value sign. But there is a - outside the first one so the -4 does become positive but then becomes negative again so you have -4

The second value is basically saying the same thing as -1x-4 which become a negative times a negative which is positive. You end up with 4.

So no it does not equal each other.

I do see an extra absolute value symbol though on the right side of the equal sign. But it looks like either way it would be -4 = 4 and that's not true. So either way it should be false.

6 0

3 years ago

Is 5 5/6 + 1 3/4=5 1/12 reasonable

ira [324]

Answer:

No, it is unreasonable.

Step-by-step explanation:

5/5/6+1/3/4=35/6+7/4

=70/12+21/12

=91/12

=7 7/12

4 0

3 years ago

Select the equivalent expression

slava [35]

Answer: c
hope this helps!

7 0

3 years ago

Apply the distributive property to create an equivalent expression.

Bumek [7]

Given:

The expression is

$(1-2g+4h)\cdot 5$

To find:

The equivalent expression.

Solution:

Distributive property of multiplication over addition is

$a(b+c)=ab+ac$

Where, a, b and c are real numbers.

We have,

$(1-2g+4h)\cdot 5$

Using distributive property, we get

$=(1)\cdot 5+(-2g)\cdot 5+(4h)\cdot 5$

$=5-10g+20h$

Therefore, the expression $5-10g+20h$ is equivalent to the given expression.

8 0

3 years ago

Read 2 more answers

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago