It is D if u did the math right
<span>Let be A= 6x6 − x3y4 − 5xy5 and B= 4x5y + 2x3y4 + 5xy5
and when we do their difference, it is A - B =
6x6 − x3y4 − 5xy5 -( 4x5y + 2x3y4 + 5xy5)=6x6 − x3y4 − 5xy5 - 4x5y - 2x3y4 - 5xy5 = 6x6 - x3y4 - 2x3y4 - 5xy5 -4xy5 -5xy5=6x6 - 3x3y4 -14xy5, so the final solution is A - B =6x6 - 3x3y4 -14xy5, the degree of this is equal to the degree of - 3x3y4, and it is 3+4=7, the answer is
The difference has 3 terms and a degree of 7.</span>
Answer:
y=15
x=43
(any variable can be used, I used x and y to make it easier to show)
Step-by-step explanation:
x+y=58
x-y=28
get x by its self
x=58-y
then subsitute into the other equation
(58-y)-y=28
58-2y=28
-2y=-30
y=15
sub. again
x+15=58
x=43
Answer:
108 miles
Step-by-step explanation:
Given the points (0.5, 135) and (2,81)
Diatnce between two points :
D = √(x2 - x1)² + (y2 - y1)²
X1 = 0.5 ; y1 = 135 ; x2 = 2 ; y2 = 81
D = √(2^2 - 0.5^2) + (81^2 - 135^2)
D = √(4 - 0.25) + (6561 - 18225)
D = √3.75 −11664
D = 107.98263
D = 108 miles
We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
