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antiseptic1488 [7]

4 years ago

10

Are two ratios are equivalent to two thirds

1 answer:

trapecia [35]4 years ago

7 0

2:3 and 4:6 are two different ratios that are equivalent to 2/3.

B)

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4x²-y²=171 and 2x-y=9, value of 2x+y

Anna007 [38]

So you will need to solve for x and y before evaluating 2x+y....

2x-y=9, y=2x-9 now this will make 4x^2-y^2=171 become:

4x^2-(2x-9)^2=171

4x^2-(4x^2-36x+81)=171

36x-81=171

36x=252

x=7, now we can use 2x-y=9 to solve for y...

2(7)-y=9

14-y=9

-y=-5

y=5

now we know that x=7 and y=5, 2x+y becomes:

2(7)+5

14+5

19

4 0

3 years ago

A roller coaster can take 162 passengers around the track in nine minutes. The roller coaster operates at a constant rate.

aivan3 [116]

Answer:

<u>18</u> passengers the roller coaster can take around the track per minute.

Step-by-step explanation:

Given:

A roller coaster can take 162 passengers around the track in nine minutes. The roller coaster operates at a constant rate.

Now, to find the number of passengers roller coaster take around the track per minute.

As given in 9 minutes the roller coaster track 162 passengers.

So, we solve by using unitary method:

In 9 minutes the roller coaster take passengers = 162.

Thus, in 1 minute it can take $=162\div 9 = 18.$

Therefore, 18 passengers the roller coaster can take around the track per minute.

5 0

3 years ago

Help pelaseeeeeeeee

monitta

Answer:

A or C

Step-by-step explanation:

5 0

4 years ago

-25 Points-<br> Find the area of the LARGER sector.<br> Leave your answer in terms of pi.

Pavlova-9 [17]

Answer:

33 pi

Step-by-step explanation:

Area of the larger sector = Area of the circle - Area of the smaller sector

Area of the circle = (6)^2 pi = 36 pi

Area of the smaller sector = 1/2 × (6)^2 × theta....,where theta has to be in radians

30° = pi/6

Area of the smaller sector = 1/2 × 36 × pi/6

= 3 pi

Area of the larger sector = 36 pi - 3 pi

Area = 33 pi

3 0

3 years ago

How many points of intersection are there between the graphs of the hyperbola and ellipse?

N76 [4]

The point of intersection is the point where two or more functions meet.

The graphs of the hyperbola and ellipse have 0 point of intersection

The given parameters are:

$\mathbf{3x^2 - 4y^2 + 4x - 8y + 4 = 0}$

$\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 0}$

To determine the points of intersection, we simply equate both equations.

So, we have:

$\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 3x^2 - 4y^2 + 4x - 8y + 4 }$

Cancel out the common terms

$\mathbf{y^2 - 3y = - 4y^2 - 8y }$

Collect like terms

$\mathbf{y^2 +4y^2= 3y - 8y }$

$\mathbf{5y^2= - 5y }$

Divide through by 5

$\mathbf{y^2= - y}$

Divide through by y

$\mathbf{y= -1}$

<em>The system of equation does not give room to calculate the x-coordinate at the x-axis.</em>

<em />

Hence, the graphs of the hyperbola and ellipse have <em>0 point of intersection</em>

Read more about points of intersection at:

brainly.com/question/13373561

4 0

3 years ago