Answer:
-8/45
I hope this helped!
Step-by-step explanation:
-2/3 ÷ 3 3/4
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):

second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:

Therefore runner B has the smaller period
Step-by-step explanation:
Simple interest is a method to calculate the amount of interest charged on a sum at a given rate and for a given period of time.
...
Simple Interest Example:
Simple Interest
1 Year S.I = (1000 ×5 × 1)/100 = 50
2 Year S.I = (1000 × 5 × 2)/100 = 100
3 Year S.I = (1000 ×5 × 3)/100 = 150
Answer:
0.497
Step-by-step explanation:
Using the binomial probability formula :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
From the question :
n = 6 ; x = 3 ; p = 0.42
P(x = 3) +... P(x = 6)
P(x = 3) = 6C3 * 0.42^3 * (1 - 0.42)^(6-3)
P(x = 3) = 20 * 0.074088 * 0.195112
P(x = 3) = 0.28910915712
Then find p(x = 4).. + p(x = 6)
Using a calculator :
P(X >= x) = 0.497