USE The two Approches, FindThe lCM OF 48, 60,72
1 answer:
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Answer:
10 square meters will have a standard deviation of 1.897.
Step-by-step explanation:
Standard deviation for n instances of a variable:
If the standard deviation for one instance of a variable is , for n instances of the variable, the standard deviation will be of
The standard deviation of the number of flaws per square yard is 0.6
This means that
For the 10 square yards will a standard deviation of
, so:
10 square meters will have a standard deviation of 1.897.
Answer:
Correct option (c).
Step-by-step explanation:
The experiment consists of determining whether the people who purchase fast-food hamburgers would be willing to pay more if the hamburger comes with a free whistle.
The hypothesis for this test is defined as:
<em>H</em>₀: The mean amount the customers are willing to pay when they are told about the free whistle is no different than the amount customers are willing to pay when they are not told they will receive a free whistle, i,e. <em>μ</em> = 0.
<em>Hₐ</em>: The mean amount the customers are willing to pay when they are told about the free whistle is different than the amount customers are willing to pay when they are not told they will receive a free whistle, i,e. <em>μ</em> ≠ 0.
The significance level of the test is, <em>α</em> = 0.05.
The test statistic is defined as:
The value of test statistic is, <em>z</em> = 3.60.
<u>Decision rule</u>:
If the <em>p</em>-value of the test statistic is less than the significance level then the null hypothesis will be rejected and vice versa.
The <em>p</em>-value of the test is,
*Use a <em>z</em>-table for the probability.
The <em>p</em>-value = 0.0004 < <em>α</em> = 0.05.
The null hypothesis will be rejected since the <em>p</em>-value is less than the significance level.
<u>Conclusion</u>:
Telling customers they will receive a free whistle with their hamburger had a significant effect on the amount they say they are willing to pay for a hamburger, <em>z</em> = 3.60, <em>p</em> < .05.