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4vir4ik [10]
3 years ago
15

51x67+90/57/72= my daughter cant figure out this question

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

3417.021

Step-by-step explanation:

Hope this helps.

Katarina [22]3 years ago
7 0
51x67=3417+90=3507/72=3418.25
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Help me please with this
telo118 [61]

Answer:

Its a

Step-by-step explanation:

A integer is like a whole number by it self

5 0
3 years ago
70 points!!!! Find the horizontal and the vertical components of f.
choli [55]

Answer:

  • F = (16.74, -2.95)

Explanation:

<u />

<u>1) Horizontal component</u>

The horizontal component is related to the magnitude of the force by the cosine ratio:

  • cos (α) = Fx / | F |

Where α in the angle (-10º), Fx is the horizontal component, and | F | is the magnitude of the force (17).

  • cos(-10º) = Fx / 17 ⇒ Fx = cos (-10º) × 17 = 16.74

<u />

<u>2) Vertical component</u>

The vertical component is related to the magnitude of the force by the sine ratio:

  • sin (α) = Fy / | F |

Where α in the angle (-10º), Fy is the vertical component, and | F | is the magnitude of the force (17).

  • sin(-10º) = Fy / 17 ⇒ Fy = sin (-10º) × 17 = -2.95

<u />

<u>3) Form (x,y)</u>

  • F = (16.74, -2.95)
6 0
3 years ago
Which angles are corresponding angles?
Mrac [35]
The answer would be angles UVX and RSQ.
Hope this helps
6 0
3 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
The producer of the news station posted an article about the high school's football championship ceremoney on a new website. The
-Dominant- [34]
Let x be the number of hours and Let y be the number of views.

x              y
1             125 
2              250
3               375
4            500
5            625
3 0
3 years ago
Read 2 more answers
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