I'd say yes. If you use the diagonal as a reference. Take the square and set your compass to the width of the diameter of the square. Now put it on the page and mark a point. Put the point of the compass on that mark and make another mark. Now you can connect the two marks with the straight edge and you have a line that, if you made a square with sides that long, it'd have 2x the area of the first one. That's because the diagonal is the square root of 2 larger than one side. Square the square root of 2 and you've got 2. You lust need to make a perpendicular line to the first one to get the box going.
F(x)=x^2+3x+5
f(3+h)=(3+h)^2+3(3+h)+5
f(3+h)=9+6h+h^2+9+3h+5
f(3+h)=23+9h+h^2
The answer is no. No matter how you do it two mixed numbers will never be a whole and even 2
The answer is D
2x - 3y = 6 multiply this by -3
3x - y = 2 Multiply this by 2
-6x + 9y = -18
6x - 2y = 4 Add the 2 equations:-
7y = -14 so y = -2
Substitute y = -2 in second equation:-
3x - (-2) = 2
3x = 2-2 = 0
x = 0
solution is (0,-2)
Answer:
x = 112
Step-by-step explanation:
1/8x + 2 = 16
Subtract 2 from both sides
1/8x = 14
Multiply both sides by 8
x = 112
