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ollegr [7]
3 years ago
10

The maximum number of charms that will fit on a bracelet is 3(d-2/3), where d is the diameter (In centimeters) of the bracelet.

Mathematics
2 answers:
Yuliya22 [10]3 years ago
8 0

Answer:

16

Step-by-step explanation:

The problem would look like this: 3(6-2/3).

First of all you would have to multiply both 6 and 2/3 by 3, resulting in a new equation, 18/1 - 2/1. Then, you can proceed to subtract 2 from 18 and you get 16.

viva [34]3 years ago
6 0

Answer: 16

the maximum number of charms that fit on a bracelet that has a diameter of 6 centimeters is 3(6 - 2/3) = 16

Step-by-step explanation:

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Answer:

Formula for mean in grouped data

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3 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
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lilavasa [31]

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