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andrey2020 [161]
3 years ago
9

Marley Works how to beat store she has 4 and 3/4 pounds of beads she is making 1/8 lb packages how many packages will she be abl

e to make
Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0
Change the 3/4 to 6/8. So then it will be 4 and 6/8 divided by 1/8= 38
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Using the congruency statement, select which statements are true.
Nataly [62]

Answer:

Using the congruency statement, select which statements are true.

Triangle W X Y is congruent to triangle E F G.

Segment W X is congruent to segment F G

Segment W Y is congruent to segment E G

Angle X is congruent to angle F

Angle G is congruent to angle W

Step-by-step explanation:

<h2>Answer is B </h2>

The answer in bold letters. I just tool the test.

4 0
3 years ago
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Students of Grade 5 together sold T- shirts for a 6 fundraiser at $ 360. Find the average number of T- shirts each student sold
vekshin1

Answer:

$60

Step-by-step explanation:

360 is for 6 T-shirt, so 1 T-shirt is:

$360 : 6 = $60

note: I feel like this question has a wierd wording

5 0
2 years ago
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What is the value of y in the equation 5x+2y=20 when x=0.3
MakcuM [25]
5 multiplied by .3 is 1.5
1.5 + 18.5 = 20.
y = 9.25
3 0
2 years ago
The temperature today was 10 degrees colder than twice yesterday's temperature, t.
Aneli [31]

Answer:  Today's temperature : 2t -10

Step-by-step explanation:

Hi, to write the expression of the statement given we have to analyze each phrase:

<em>Twice yesterday's temperature, t.</em> If t is yesterday’s temperature, twice that temperature equals 2t.

<em>The temperature today was 10 degrees colder than</em>: It means that we have to subtract 10 degrees :(-10)

Mathematically speaking:

Today's temperature : 2t -10

where t = yesterday's temperature

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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