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3 years ago

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Secondly, a man is rock climbing when suddenly the rock face he grabs breaks away and he is left with a 1200 lb. rock on his che

st. How do scientists say he was able to lift this incredible weight and save himself

1 answer:

lord [1]3 years ago

5 0

Answer:

rush of adrenaline

Explanation:

This is believed to have been possible due to the rush of adrenaline that the individual was experiencing. This has happened a couple times in moments of extreme distress where an individual's body is flooded with adrenaline. This adrenaline allows for super human like strength as well as increased senses. The individual that has lifted the most amount of weight in such a scenario, lifted a total of 3000 lbs. Therefore, it is fair to say that 1200 lb. rock was lifted due to adrenaline.

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A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci

Simora [160]

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

4 0

3 years ago

An electric field exerts a force of 3.00 E -4 N on a positive test charge of 7.20 E-4 C. The magnitude of the field at this loca

Step2247 [10]

3.00 E-4 / 7.20 E-4 = 0.417
answer is b

3 0

4 years ago

Read 2 more answers

The diffusion coefficients for species A in metal B are given at two temperatures: T (°C) D (m2/s) 1030 6.11 × 10-17 1250 6.02×

Karo-lina-s [1.5K]

Answer:

(a). The value of the activation energy is 171565.80 J/mol.

(b). The value of D₀ is $1.652\times10^{10^{-8}}\ m^2/s$

(c). The magnitude of D at 1160°C is $5.067\times10^{-8}\ m^2/s$

Explanation:

Given that,

Temperatures,

$T_{1}=1030^{\circ}C$

$T_{2}=1250^{\circ}C$

Diffusion coefficients are

$D_{1}=6.11\times10^{-17}$

$D_{2}=6.02\times10^{-16}$

(a). We need to calculate the value of the activation energy

Using relation between diffusion coefficient and temper

$ln(D_{1})=ln(D_{0})-(\dfrac{Q_{d}}{RT_{1}})$ ....(I)

$ln(D_{2})=ln(D_{0})-(\dfrac{Q_{d}}{RT_{2}})$ .....(II)

Divided equation (II) by (I)

$ln(\dfrac{D_{2}}{D_{1}})=\dfrac{Q_{d}}{R}\times(\dfrac{1}{T_{1}}-\dfrac{1}{T_{2}})$

Put the value into the formula

$ln(\dfrac{6.02\times10^{-16}}{6.11\times10^{-17}})=\dfrac{Q_{d}}{8.314}\times(\dfrac{1}{1030+273}-\dfrac{1}{1250+273})$

$Q_{d}=\dfrac{2.2877\times8.314\times1984469}{220}$

$Q_{d}=171565.80\ J/mol$

(b). We need to calculate the value of D₀

Using relation between diffusion coefficient and temperature

$ln(D_{0})=ln(D)+(\dfrac{Q_{d}}{RT_{1}})$

Put the value of in to the formula

$ln(D_{0})=ln(6.11\times10^{-17})+(\dfrac{171565.80}{8.314\times1030+273})$

$ln(D_{0})=-17.9182$

$D_{0}=e^{-17.9182}$

$D_{0}=1.652\times10^{10^{-8}}\ m^2/s$

Now again put the value in the equation (II)

$ln(D)=ln(1.652\times10^{10^{-8}})-(\dfrac{171565.80}{8.314\times1160+273})$

$ln(D_{0})=-16.79776$

$D_{0}=e^{-16.79776}$

$D_{0}=5.067\times10^{-8}\ m^2/s$

Hence, (a). The value of the activation energy is 171565.80 J/mol.

(b). The value of D₀ is $1.652\times10^{10^{-8}}\ m^2/s$

(c). The magnitude of D at 1160°C is $5.067\times10^{-8}\ m^2/s$

8 0

3 years ago

How is the polarization of an electromagnetic wave defined? Group of answer choices The polarization is defined by the plane in

Anarel [89]

Answer:

The polarization is defined by the plane in which the electric field is oscillating.

Explanation:

The polarization of an electromagnetic wave depends on the direction of the electric field. If the electric component is oscillating along the x-axis, the polarization will also be along the x-axis.

The polarization of the electromagnetic wave describes the magnitude and the direction of the electric field of the wave.

<u>The polarization is defined by the plane in which the electric field is oscillating.</u>

7 0

3 years ago

A skydiver jumps out of a helicopter and falls freely for 5.6 s before opening the parachute. (a) What is the skydiver's downwar

PilotLPTM [1.2K]

Answer:

A. 54.88m/s.

B. 153.66m

Explanation:

Data obtained from the question include:

Time (t) = 5.6 secs

A. Determination of the skydiver's downward velocity.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Velocity (v) =..?

v = gt

v = 9.8 x 5.6

v = 54.88m/s

Therefore, the skydiver's downward velocity is 54.88m/s

B. Determination of the height below the helicopter.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Height (H) =..?

H = ½gt²

H = ½ x 9.8 x 5.6²

H = 153.66m

Therefore, the height below the helicopter when the parachute opens is 153.66m.

6 0

3 years ago