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3 years ago

The circuit below contains an ideal battery, four identical light bulbs, and a switch. The switch is initially open.

Physics

1 answer:

Dafna1 [17]3 years ago

5 0

The question is incomplete! circuit figure is attached below and answer and explanation is provided below.

Answer:

Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.

Explanation:

What happens when switch is open?

When the switch is open Bulb_C is open circuited meaning that there is no way for the current to flow through it. This path offers infinite resistance to the current therefore, current will try to take a least resistance path that is through Bulb_B.

So eventually, when the switch is open the circuit becomes a simple series circuit with path From battery to Bulb_A to Bulb_B to Bulb_D to battery with Bulb_C = 0.

What happens in a series circuit?

We know that in a series circuit, there is only one path for the current to flow therefore, same current will flow through all the series Bulbs and their brightness will be same. Bulb_A = Bulb_B = Bulb_D

Brightness in a series circuit:

We also know know that in a series circuit, resistance gets summed up and voltage across each Bulb gets shared which results in less power dissipation that's why Bulbs connected in series appear dimmer as compared to when they are connected in parallel.

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Fittoniya [83]

83 km/h * 2.5 hours (3:30 - 1:00) = 207.5 km

207.5 km - 15 km = 192.5 km

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3 years ago

Light travels at a speed of about 3.0 108 m/s. (a) how many miles does a pulse of light travel in a time interval of 0.1 s, whic

babunello [35]

Speed of light is given as

$c = 3 * 10^8 m/s$

time interval is given as

$\Delta t = 0.1 s$

so the distance covered by the light is given as

$d = v * \Delta t$

$d = 3 * 10^8 * 0.1 = 3 * 10^7 meter$

now as we know that

$1 mile = 1609 meter$

so the distance moved by light is

$d = \frac{3 * 10^7}{1609} = 18645.12 miles$

now for the comparision of this distance with diameter of earth

as we know that radius of earth is

$R = 6.38 * 10^6 m$

so the diameter of earth will be

$d = 2R = 12.76 * 10^6 m$

now the ratio of diameter with the distance that light move will be

$\frac{distance}{diameter} = \frac{3 * 10^7}{12.76 * 10^6}$

$\frac{distance}{diameter} = 2.35$

<em>so it is 2.35 times more than the diameter of earth</em>

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3 years ago

Suppose that you hear a clap of thunder 16.2 s (seconds) after seeing the associated lightning stroke. The speed of sound waves

spayn [35]

Since the speed of sound is very high, we consider the time period of thunder and lightening negligible.

Now, d = vt

thus, d = 343 x 16.2

thus, d = 5556.6 metres

Thus, we are 5556.6 metres away from lightening ( approximately)

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3 years ago

If a car is traveling forward at 15 M/S, how fast will be going in 1.2 seconds if the acceleration is 10 M/s2?

GuDViN [60]

Answer:

Vf=27m/s

Explanation:

Vf=Vi+at

Lets substitute the known variables into the equation:

Vf=15+10×1.2

Vf=27m/s

So itll be going 27metres per second

6 0

3 years ago

A block is attached to one end of a spring so that it can bounce back and forth on a horizontal frictionless surface. The block

natta225 [31]

Answer:

m = 1.35 kg

Explanation:

In absence of friction, total mechanical energy must be conserved, so the sum of the initial elastic potential energy plus the initial kinetic energy, must be equal to the sum of the final kinetic energy plus the final elastic potential energy, as follows:

$U_{i} + K_{i} = U_{f} + K_{f} (1)$

As the block starts from rest, this means that Ki =0.
We can express the elastic potential energy at any point , as follows:

$U = \frac{1}{2} * k * \Delta x^{2} (2)$

where k is the spring constant = 60.0 N/m, and Δx is the distance from

the equilibrium position.

Replacing Ui, Uf and Kf in (1), we have:

$\frac{1}{2} * k *\Delta x_{i} ^{2} =\frac{1}{2} * k *\Delta x_{f} ^{2} +\frac{1}{2} * m *v ^{2} (3)$

Replacing by the givens, and solving for m, we get:

m =1.35 kg

6 0

3 years ago