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3 years ago

The circuit below contains an ideal battery, four identical light bulbs, and a switch. The switch is initially open.

Physics

1 answer:

Dafna1 [17]3 years ago

5 0

The question is incomplete! circuit figure is attached below and answer and explanation is provided below.

Answer:

Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.

Explanation:

What happens when switch is open?

When the switch is open Bulb_C is open circuited meaning that there is no way for the current to flow through it. This path offers infinite resistance to the current therefore, current will try to take a least resistance path that is through Bulb_B.

So eventually, when the switch is open the circuit becomes a simple series circuit with path From battery to Bulb_A to Bulb_B to Bulb_D to battery with Bulb_C = 0.

What happens in a series circuit?

We know that in a series circuit, there is only one path for the current to flow therefore, same current will flow through all the series Bulbs and their brightness will be same. Bulb_A = Bulb_B = Bulb_D

Brightness in a series circuit:

We also know know that in a series circuit, resistance gets summed up and voltage across each Bulb gets shared which results in less power dissipation that's why Bulbs connected in series appear dimmer as compared to when they are connected in parallel.

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3 years ago

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3 years ago

A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 25.5 kg.

Svetllana [295]

Answer:

72.75 kg m^2

Explanation:

initial angular velocity, ω = 35 rpm

final angular velocity, ω' = 19 rpm

mass of child, m = 15.5 kg

distance from the centre, d = 1.55 m

Let the moment of inertia of the merry go round is I.

Use the concept of conservation of angular momentum

I ω = I' ω'

where I' be the moment of inertia of merry go round and child

I x 35 = ( I + md^2) ω'

I x 35 = ( I + 25.5 x 1.55 x 1.55) x 19

35 I = 19 I + 1164

16 I = 1164

I = 72.75 kg m^2

Thus, the moment of inertia of the merry go round is 72.75 kg m^2.

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3 years ago

PART ONE

lawyer [7]

Answer:

(a) 58 cm

(b) 591.4 Hz

Explanation:

(a)

For closed organ pipe, the wavelength is given by

$\lambda=\frac {4L}{2n-1}$ where $\lambda$ is wavelength, L is the length of the pipe and n is the resonance

Substituting 217.5 m for L and 8 for n then the wavelength of the sound will be

$\lambda=\frac {4\times 217.5}{(2\times 8)-1}=58 cm$

(b)

We know that the speed of sound, v is a product of frequency and wavelength.

$v=\lambda f$

Making frequency the subject of the formula then

$f=\frac {v}{\lambda}$ and since the velocity is given as 343 m/s and wavelength is already found in part a above but now we change units from cm to m then