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viva [34]
3 years ago
12

A skydiver jumps out of a helicopter and falls freely for 5.6 s before opening the parachute. (a) What is the skydiver's downwar

d velocity when the parachute opens? Correct: Your answer is correct. m/s (b) How far below the helicopter is the skydiver when the parachute opens? Incorrect: Your answer is incorrect. m
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

A. 54.88m/s.

B. 153.66m

Explanation:

Data obtained from the question include:

Time (t) = 5.6 secs

A. Determination of the skydiver's downward velocity.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Velocity (v) =..?

v = gt

v = 9.8 x 5.6

v = 54.88m/s

Therefore, the skydiver's downward velocity is 54.88m/s

B. Determination of the height below the helicopter.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Height (H) =..?

H = ½gt²

H = ½ x 9.8 x 5.6²

H = 153.66m

Therefore, the height below the helicopter when the parachute opens is 153.66m.

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A rescue airplane is diving at an angle of 37o below the horizontal with a speed of 250 m/s. It releases a survival package when
igomit [66]

Answer:

796.2 m.

Explanation:

A sketch of the given question forms a right angled triangle with two given sides and a non included angle. Applying the appropriate trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

Let the horizontal distance required be represented by x, so that;

Tan 37^{o} = \frac{600}{x}

0.7536 = \frac{600}{x}

⇒ x = \frac{600}{0.7536}

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5 0
3 years ago
Cuanto es tres por dos más cinco<br>3 * 2 + 5 es igual ​
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Answer:

3×2+5=11

Explanation:

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4 0
3 years ago
An object that floats in water weighs 20 N in air.
Licemer1 [7]

Answer:

a. Weight of Object in Water = 20 N

b. Up thrust = 20 N

c. Weight of Water Displaced = 20 N

Explanation:

a.

The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,

<u>Weight of Object in Water = 20 N</u>

<u></u>

b.

Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:

Up thrust = Weight of object

<u>Up thrust = 20 N</u>

<u></u>

c.

From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:

Weight of Water Displaced = Up thrust

<u>Weight of Water Displaced = 20 N</u>

7 0
3 years ago
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