Help me!!!

Mathematics

1 answer:

Masja [62]2 years ago

3 0

Answer:

Depends, I do that sometimes out of love and just for fun however i let them know im doing it just to mess with them. If you feel like they dont like you or you think they are a fake friend just get rid of them because later on it will break you as a person rather than make you a better person. Id suggest surrounding yourself around better peopl/frienda

Step-by-step explanation:

i dont know lol just what came off the top of my head

You might be interested in

What value of x makes this proportion true? 36/48 = x/24

ruslelena [56]

Answer:

Step-by-step explanation:

18/24 is a 1/2 reduction from 36/48.

3/4 is simplest form.

8 0

2 years ago

The surface area of the world is about 7/10 water. If a very small, non-dangerous meteoroid lands on the earth, what is the prob

galben [10]

Answer: 3/10 probability

Step-by-step explanation:

We are telling the probability with tenths, so we can say that the probability of the meteoroid landing on Earth is 3/10.

If the surface area of the world is approximately 7/10, or 70 percent, water, there is approximately 3/10, or 30 percent, chance of the meteoroid hitting land.

I'm pretty sure, at least ^_^

7 0

3 years ago

Read 2 more answers

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$