The answer would be 6w^5y^3
Imagine a right triangle where a and b are the legs and c is the hypothenuse.
Pitagora: a²+b²=c²
Divide by c
(a/c)²+(b/c)²=1
But a/c=sin(B) and b/c=cos(B)
Thus sin² + cos² = 1
Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.
Answer:
24.58
Step-by-step explanation:
Rounded to the nearest 0.01 or the Hundredths Place.
Answer:
Q1: The rabbit could be at eight different numbers of the number line: -7, - 5, - 3, - 1, 1, 3, 5, and 7.
Q2: 13
Step-by-step explanation:
Q1: Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:
Option 1: - 4 - 2 - 1 = -7
Option 2: - 4 - 2 + 1 = -5
Option 3: - 4 + 2 - 1 = - 3
Option 4: - 4 + 2 + 1 = - 1
Option 5: 4 - 2 - 1 = 1
Option 6: 4 - 2 + 1 = 3
Option 7: 4 + 2 - 1 = 5
Option 8: 4 + 2 + 1 = 7
Q2: If the rabbit started at 10 you would add 3 to 10 and get 13.
