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3 years ago

Please help me on this!!

Mathematics

2 answers:

Solnce55 [7]3 years ago

8 0

Step-by-step explanation:

a) Hong is not a member of i. music and Dance

b) 2 students which is Eric and Omar

c). Mai , Hong,Ryan and lena

Alex17521 [72]3 years ago

5 0

Answer:

(a). Music and dance.

(b). Three students.

(c). Hong, Ryan, Lena and Mai

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If 9^(1 - x) =27^Y and x-y equals to -11 / 2 find the value of x + y

777dan777 [17]

Answer:

x = -2.9

y = 2.6

x+y = -2.9+2.6

= -0.3

8 0

3 years ago

Please answer this question

Tems11 [23]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :- </h3>

• $\sf{ Polynomial :- ax^{2} + bx + c }$

• The zeroes of the given polynomial are α and β .

<h3>Let's Begin :- </h3>

Here, we have polynomial

$\sf{ = ax^{2} + bx + c }$

We know that, 

Sum of the zeroes of the quadratic polynomial

$\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}$

And 

Product of zeroes

$\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}$

Now, we have to find the polynomials having zeroes :-

$\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}$

Therefore ,

Sum of the zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}$

$\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}$

$\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}$

$\bold{{\dfrac{ -bc - ab}{ac}}}$

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

Product of zeroes

$\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}$

$\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}$

$\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The product of the zeroes are c/a + a/c + 2 .

We know that, 

For any quadratic equation

$\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }$

$\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}$

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3>Some basic information :-</h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0

2 years ago

Write the equation of a line whose slope is -2 and goes through the point (1,-1)

scoundrel [369]

Answer:

y= -2x+1

Step-by-step explanation:

y=mx+b

Substitute the ordered pairs into the equation

So:

y= -1 m(slope) = -2 x=1 b=?

-1 = (-2)(1) + b

-1 = -2 +b add 2 on both sides to get b by itself

-1 +2 = b

b=1

8 0

3 years ago

In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.

nydimaria [60]

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(\angle J)=\frac{22}{54}$

Using inverse sine or arcsin, we will get:

$\angle J=\text{sin}^{-1}(\frac{22}{54})$

$\angle J=24.042075905756^{\circ}$

Upon rounding to nearest degree, we will get:

$\angle J\approx 24^{\circ}$

Therefore, the measure of angle J is approximately 24 degrees.

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4 years ago

I need help. What’s the answer and how do you do this?

erik [133]

Scale factor is 1/2 or 0.5

One of the sides of figure A is 4 units, Same side for Figure B has TWO units.
Which is basically half the size of the original (figure A)

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4 years ago