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Artemon [7]
3 years ago
10

La sombra que proyecta un edificio es de 16 m si el coseno del ángulo que se forma entre la punta de la sombra y el techo del ed

ificio es 16/20 cual es la altura del edificio
Mathematics
1 answer:
AlekseyPX3 years ago
6 0

Answer:

dont understand clearly

Step-by-step explanation:

dont understand clearly

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to pour the concrete sidewalk approximately how many cubic feet of topsoil will you need to remove for the 4"thick sidewalk if t
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Answer:

i have no clue I just need extra points

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3 years ago
Find the sum using the number line. 3+(-4) *<br><br> A -1<br> B 1<br> C 7<br> D -7
Novay_Z [31]
A. -1 is your answer.
6 0
3 years ago
Read 2 more answers
Irene treated her coworkers show me that cost $30 I renew that when the bill came she would have to pay Lewisburg sale tax of 10
baherus [9]

Answer:

$39

Step-by-step explanation:

The cost of the treat was $30, with the addition of a 10% sale tax and a 20% tip on the original $30.

So, total of (10 + 20) = 30% extra cost she has to pay on the original $30.

Hence, the total amount to be paid for the meal will be

30(1 + \frac{30}{100}) = 39 dollars. (Answer)

5 0
3 years ago
An article presents a study of health outcomes in women with symptoms of heart disease. In a sample of 110 women whose test resu
REY [17]

Answer:

(0.869, 12.33104)

Step-by-step explanation:

N1 = 110

N2 = 225

S1 = 24.8

S2 = 25.8

Bar x1 = 169.9

Bar x2 = 163.3

Difference in mean = 169.9 - 163.3 = 6.6

We use the z score

Alpha = 0.05

Z critical value at this alpha level = 1.96

We find standard error

√s1²/n1+s2²/n2

= √(24.8²/110 + 25.8²/225)

= 2.9239

Confidence interval

6.6 +-1.96(2.924)

(6.6-5.73104, 6.6+5.73104)

= (0.869, 12.331)

4 0
3 years ago
URGENT: statistics: A researcher wishes to estimate the percentage of adults who support abolishing the penny what size sample s
irina1246 [14]

Using the margin of error for the z-distribution, the sample sizes are given as follows:

a) 822.

b) 1068.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

We have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Item a:

The estimate is of \pi = 0.26, hence we solve for n when M = 0.03.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.26(0.74)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.26(0.74)}

\sqrt{n} = \frac{1.96\sqrt{0.26(0.74)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.26(0.74)}}{0.03}\right)^2

n = 821.2

A sample of 822 is needed.

Item b:

No prior estimate, hence \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1067.11

A sample of 1068 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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