Hi can u help me with this please
1 answer:
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The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Given:
f(x) = ln(x)
n = 4
c = 3
nth Taylor polynomial for the function, centered at c
The Taylor series for f(x) = ln x centered at 5 is:
Since, c = 5 so,
Now
f(5) = ln 5
f'(x) = 1/x ⇒ f'(5) = 1/5
f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25
f'''(x) = 2/x³ ⇒ f'''(5) = 2/5³ = 2/125
f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625
So Taylor polynomial for n = 4 is:
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Hence,
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Find out more information about nth taylor polynomial here
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Answer:
The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.
Step-by-step explanation:
Using Pythagoras' Theorem, a²+b² = c² :
Let a be x cm,
Let b be x+7 cm,
Let c be 2x+1 cm
x² + (x+7)² = (2x+1)²
x² + x² + 14x + 49 = 4x² + 4x + 1
2x² + 14x + 49 = 4x² + 4x + 1
Then, move all the variables to one side and solve it to find the value of x :
4x² + 4x + 1 - 2x² - 14x - 49 = 0
2x² - 10x - 48 = 0
2(x² - 5x - 24) = 0
x² - 5x - 24 = 0
(x-8)(x+3) = 0
x - 8 = 0
x = 8 cm
x + 3 = 0
x = -3 cm (rejected)
Substitute the x value into the length of a,b and c :
a = x
= 8 cm
b = x + 7
= 8 + 7
= 15 cm
c = 2x + 1
= 2(8) + 1
= 16 + 1
= 17 cm
Actually yeah. It’s really annoying
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