Answer:
6x ≥ 3 + 4(2x - 1)
⇔ 6x ≥ 3 + 8x - 4 => remove the parentheses
⇔ 6x - 8x ≥ 3 - 4
⇔ -2x ≥ -1
⇔ 2x ≤ 1 (or 1 ≥ 2x)
⇔ x ≤ 1/2
⇔ x ≤ 0.5
The answer for the question should be:
1 ≥ 2x
6x ≥ 3 + 8x – 4
and the first graph.
Answer:
9
Step-by-step explanation:
1, 3, 5, 9, 15, 19, 19
Answer:
-4
Step-by-step explanation:
2(-3+1)
Distribute: -6 - (-2)
Answer: -4
The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Step-by-step explanation:
A bisector is a line that divides a line segment in two equal parts. A perpendicular bisector is a line that is perpendicular to given line segment and passes through the mid-point of the line segment. It can also be said as that the line perpendicular to a line segment that divides the lines in half is called the perpendicular bisector.
The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Keywords: Perpendicular, bisector
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Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
