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frozen [14]
2 years ago
5

The total cost to rent a row boat is $14 times the

Mathematics
1 answer:
Artyom0805 [142]2 years ago
7 0

Answer:

is you rent the boat for 14 dollars for an hour then I think it would be 12 hours you could use the boat for I'm not sure

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How would you write the equation ????
Elden [556K]
If f(x)=e^x-1 +5 and g(x) is a transformation or, the same thing just moved, and its y-intercept is -3 then its equation would be:

D) g(x)=e^x-1 -3
8 0
3 years ago
Use the power property to rewrite log3x9.
posledela
For properties of logarithm we have the following:
 loga (x ^ b) = b * loga (x)
 Therefore, following this property we have for this case:
 log3 (x ^ 9) = 9log3 (x)
 Answer:
 
the power property to rewrite log3x9 is:
 
B) 9log3x
4 0
3 years ago
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Hey factory can produce fifth refrigerators in eight hours how many hours would it take to produce 1250 refrigerators
jarptica [38.1K]

Hey, I'm assuming you mean five refrigerators every eight hours. So . . .

1250 divide by 5. Which gives you 250.

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6 0
3 years ago
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Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
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Write the equation of the line that passes through the given points in slope intercept form
shepuryov [24]

Answer:

y=3x

Step-by-step explanation:

To put this in slope intercept form, let’s first find the slope

To find slope, use the equation Y2-Y1/X2-X1

When we do this, we get 0-6/0-2

This simplifies out into -6/-2 which is 3

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Now, we find our b

We don’t have to do any solving for this, since we have the point 0,0 listed for us, it goes through the origin and that is our y-intercept or b

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2 years ago
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