With each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5.
<h3>What is slope-intercept form?</h3>
The slope-intercept form is just a means of stating a line's equation so that both the slope (steepness) as well as y-intercept (where another line crosses this same vertical y-axis) are obvious. This expression is frequently referred to as y = mx + b.
<h3>According to the given information:</h3>
To begin, are using the slope formula to figure out the average slope between two points here.
Let:
x1 = 4
y1 = -1
x2 = -2
y2 = -1
m = (y2-y1)/(x2-x1)
= (-1 - (-1))/ (4-(-1))
= 0/5
= 0
So the slope is 0.
We must now calculate the y-intercept. This will be accomplished by converting a single of the points and also the slope together into a point-slope linear equation. y2-y1 = m(x2-x1).
Let’s plug in the point (5,0).
So we get y-(-0) = (0/5)(x-(-5)) ⇒ y+0
= (0/5)x + 0 ⇒ y
So,
Y = 0
X = 5
with each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5
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Answer: D
Step-by-step explanation:
Standard Deviation σ2 =
Σ(xi - μ)2/N
=(1 - 5.3)2 + ... + (9 - 5.3)2/10
=68.1/10
= 6.81
σ = √6.81
= 2.60959767014
B) σ2 =
Σ(xi - μ)2/N
=(3 - 61.7)2 + ... + (99 - 61.7)2/10
=58414.1/10
= 5841.41
σ = √5841.41
= 76.429117488036
C) (1 - 11.4)2 + ... + (1 - 11.4)2/10
=8758.4/10
= 875.84
σ = √875.84
= 29.59459410095
D) (79 - 79)2 + ... + (79 - 79)2/10
=0/10
= 0
σ = √0
= 0
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Answer:
When we simplify the problem we get 33/8
Answer:
y = (-14/15) x + (11/15)
Explanation:
The slope-intercept form has the following formula:
y = mx + c
where:
m is the slope
c is the y-intercept
The given is:
14x + 15y = 11
To put this in slope-intercept form, we will need to isolate the y as follows:
14x + 15y = 11
15y = -14x + 11
y = (-14/15) x + (11/15)
were:
m is the slope = -14/15
c is the y-intercept = 11/15
Hope this helps :)
Answer: .The graph is a line that rises steeply from left to right and passes through the origin. 2.The graph is a line that rises gradually
Step-by-step explanation: hope tha help
