T.S.A. = pi (7) (24) + pi (7)^2 = 168pi + 49pi = 217 pi cm^2 = more or less 681,73 cm^2
Answer:
yessssss
Step-by-step explanation:
hope this helps
10 or 25 and a lot more pretty much anything that ends with 0 or 5
Answer:
5 shirts must be sold.
Step-by-step explanation:
First, set up the equation. Each shirt (x) is sold for $16:
For every amount (y) for x: (y)(x) = (16)(y)
The cost is $4, with the setup fee as $60.
(16)(y) = (4)(y) + 60
16y = 4y + 60
Isolate the variable (y). Note the equal sign, what you do to one side, you do to the other. First, subtract 4y from both sides.
16y (-4y) = 4y (-4y) + 60
16y - 4y = 60
12y = 60
Next, isolate the variable (y). Divide 12 from both sides.
(12y)/12 = (60)/12
y = 60/12
y = 5
5 shirts must be sold.
To check, plug in 5 for y in the equation:
16y = 4y + 60
16(5) = 4(5) + 60
Simplify.
16(5) = 4(5) + 60
80 = 4(5) + 60
80 = 20 + 60
80 = 80 (True).
~
Remember when you learning about the "Least Common
Multiple" and you wondered when in the world you would
ever need to use it ?
Well, here you are ! Hello !
The next time they will cross the starting line together is the
LCM (Least Common Multiple) of 30 and 40 .
Do you remember how to find it ?
Here's one easy way:
Count by 30s until you come to a number that's divisible by 40 .
Laura's first lap. . . . . . . . 30 seconds . . . not divisible by 40
Laura's two laps . . . . . . . 60 seconds . . . not divisible by 40
Laura's three laps. . . . . . 90 seconds . . . not divisible by 40
Laura's four laps. . . . . . 120 seconds . . . divisible by 40
After 120 seconds, Laura has completed four laps,
Shelby has completed only three laps.
