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Burka [1]
3 years ago
6

The average rate of a printer is 4 seconds per page. At this rate, how many pages will be printed in 3 minutes?

Mathematics
2 answers:
denpristay [2]3 years ago
6 0
I think the answer is 45 because, I made 3 minutes into seconds and got 180 seconds then I divided it by 4 and got 45. Your welcome
motikmotik3 years ago
4 0

Answer:

45

Step-by-step explanation:

each second we print 1/4 or 0.25 pages

0.25 x 60 seconds = 15 pages every minute

15 x 3 minutes = 45 pages in 3 minutes

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What are the x-intercepts of the graphs of the function shown below y=x^2+4x-32?
stellarik [79]
They are  x = 8 and x = -4
5 0
3 years ago
Is the sum of two angles sometimes , always , or never an obtuse angle ?
k0ka [10]
An obtuse angle would be an angle more then 90 degrees.

So if you add two angles together, it could be less then 90 degrees, such as 30 + 50 = 80 degrees.

However, it can also be more then 90 degrees, or an obtuse angle, for example 60 + 50 = 110 degrees.

So it's sometimes.
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3 years ago
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Round 4.88 to the nearest tenth
Minchanka [31]
4.88 rounded to the nearest tenth is 4.9
7 0
3 years ago
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The unit cost, in dollars, to produce bins of cat food is $3 and the fixed cost is $6972. The price-demand function, in dollars
stellarik [79]

Answer:

Revenue , Cost and Profit Function

Step-by-step explanation:

Here we are given the Price/Demand Function as

P(x) = 253-2x

which means when the demand of Cat food is x units , the price will be fixed as 253-2x per unit.

Now let us revenue generated from this demand i.e. x units

Revenue = Demand * Price per unit

R(x) = x * (253-2x)

      = 253x-2x^2

Now let us Evaluate the Cost Function

Cost = Variable cost + Fixed Cost

Variable cost = cost per unit * number of units

                      = 3*x

                      = 3x

Fixed Cost = 6972 as given in the problem.

Hence

Cost Function C(x) = 3x+6972

Let us now find the Profit Function

Profit = Revenue - Cost

P(x) = R(x) - C(x)

= 253x-2x^2 - (3x + 6972)

= 253x-3x-2x^2-6972\\= 250x-2x^2-6972\\=-2x^2+250x-6972\\

Now we have to find the quantity at which we attain break even point.

We know that at break even point

Profit = 0

Hence P(x) = 0

-2x^2+250x-6972=0\\

now we have to solve the above equation for x

Dividing both sides by -2 we get

x^2-125x+3486=0

Now we have to find the factors of 3486 whose sum is 125. Which comes out to be 42 and 83

Hence we now solve the above quadratic equation using splitting the middle term method .

Hence

x^2-42x-83x+3486=0\\x(x-42)-83(x-42)=0\\(x-42)(x-83)=0\\

Either (x-42) = 0 or (x-83) = 0 therefore

if x-42= 0 ; x=42

if x-83=0 ; x=83

Smallest of which is 42. Hence the number of units at which it attains the break even point is 42.

5 0
3 years ago
Determine the coordinates of the intersection of the diagonals of square ABCD with verticals A(-4,6), B(5,6) C(4,-2), and D(-5,-
timama [110]

Given:

Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).

To find:

The intersection of the diagonals of square ABCD.

Solution:

We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.

In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.

We can find midpoint of either AC or BD because both will result the same.

Midpoint of A(-4,6) and C(4,-2) is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)

Midpoint=\left(0,2\right)

Therefore, the intersection of the diagonals of square ABCD is (0,2).

4 0
3 years ago
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