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3 years ago

Select all explanation that prove triangle ABC is congruent to triangle A'B'C

Mathematics

1 answer:

Archy [21]3 years ago

3 0

Answer:

AB = A'B'

BC = B'C'

AC = A'C'

angle ABC = angle A'B'C'

angle CAB = angle C'A'B'

angle CBA = angle C'A'B'

Step-by-step explanation:

use different axomes to show relation,

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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

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3 years ago

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Over [174]

Answer:

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(8,7)

Step-by-step explanation:

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3 years ago

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Answer : 11^9
Explanation: when you’re dividing powers, you substract them, so in this case it is 6-2 and you’ll get 11^4. Then you need to multiply, when you’re multiplying you are adding powers. In this case you add 4 and 5 and get 11^9

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2 years ago

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What is 2 thirds of 60

Mkey [24]

You have to set up a proportion so 2 over 3= x over 60. So multiply 2 times 60= 120 divided by 3 which is 40

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3 years ago

The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th

Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

$C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)$

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

$dC = Cv.dv + Ct.dt$

$Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44$

Relative Error

dC / C @(T = 8, v=23) * 100 = 19 %

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3 years ago