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3 years ago

Select all explanation that prove triangle ABC is congruent to triangle A'B'C

Mathematics

1 answer:

Archy [21]3 years ago

3 0

Answer:

AB = A'B'

BC = B'C'

AC = A'C'

angle ABC = angle A'B'C'

angle CAB = angle C'A'B'

angle CBA = angle C'A'B'

Step-by-step explanation:

use different axomes to show relation,

Other possible answers:

17/15

17:15

Hope this helps you!

3 0

3 years ago

2748 mile flight 6 hours

Karo-lina-s [1.5K]

We Know, speed = Distance / Time
Here, Distance = 2748 miles
Time = 6 hours

Substitute their values in to the expression,
Speed = 2748 / 6 = 458 Miles / Hour

So, the speed would be: 458 miles/hour

Hope this helps!

7 0

3 years ago

The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three poin

ss7ja [257]

Answer:

The answer is below

Step-by-step explanation:

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

$AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:

The distance between K and L = KL = $\sqrt{(-1-3)^2+(1-4)^2} =5\ units$

The distance between J and L = JL = $\sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units$

The distance between K and J = JK = $\sqrt{(3-3)^2+(-3-4)^2} =7\ units$

Therefore, the perimeter of triangle JKL is:

Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units

8 0

3 years ago

WILL RATE BRAINLIEST PLZ HELP<br> MUST EXPLAIN THO

madreJ [45]

Answer:

A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
D -- base 3, height 5

Step-by-step explanation:

A sort of straightforward way to approach this is to define base and height variables for each of the figures: ba, ha, bb, hb, bc, hc, bd, hd. Then the statements can be used to make equations in these variables.

0. hc = bc . . . . figure C is a square

1. ba = bd

2. ba = bb -1

3. hc = ba

4. hb = ha = bb

5. hc·bc = 9

6. (1/2)ha·ba +(1/2)hb·bb +hc·bc+hd·bd = 38

Using equations 0 and 5, we find ...

hc² = 9 ⇒ hc = 3

From equation 3, ...

ba = 3

From equation 2, ...

3 = bb -1 ⇒ bb = 4

From equation 1, ...

bd = 3

From equation 4, ...

ha = hb = 4

Filling in the values we know in equation 6, we get ...

(1/2)(4)(3) +(1/2)(4)(4) +9 +hd(3) = 38

23 +3hd = 38

hd = 15/3 = 5

The dimensions are:

A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
D -- base 3, height 5

8 0

3 years ago