Answer:
Step-by-step explanation:
A discriminate of -8 is never going to give you a real root. D is wrong
You cannot have just 1 complex root, nor can you have just 1 real root unless the discriminate is 0. A and C are both wrong for the same reason. 1 complex root is impossible. They come in pairs.
So the answer is B. You have 2 complex roots.
Answer:
The Product of 7⋅(−4)⋅(−6) −168 −3 is<em> </em><u>-3</u>
The slope is 2, as for every 20 the graph rises, the line goes over 10, and the formula for slope is rise over run.
The limit does not exist at the jump discontinuity at <em>x</em> = -2.
From the left, the green-ish curve approaches 4; from the right, the orange curve approaches 6. These one-sided limits are not equal, so the two-sided limit does not exist.
Answer:
(-√(6-√26) < x < √(6-√26)) ∪ (x < -√(6 +√26)) ∪ (√(6 +√26) < x)
Step-by-step explanation:
Using x^2 = z, the equation can be rewritten as ...
z^2 -12z +10 > 0
(z -6)^2 -26 > 0
|z -6| > √26
This resolves to two equations.
This one ...
x^2 -6 < -√26 . . . . substitute x^2 for z
|x| < √(6-√26) . . . . add 6, take the square root; use √a^2 = |a|
-√(6-√26) < x < √(6-√26)
__
and this one ...
x^2 -6 > √26
|x| > √(6 +√26)
x < -√(6 +√26) ∪ √(6 +√26) < x
