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3 years ago

9

Ethan goes to a store an buys an item that costs xx dollars. He has a coupon for 5% off, and then a 9% tax is added to the disco

unted price. Write an expression in terms of xx that represents the total amount that Ethan paid at the register.

1 answer:

mestny [16]3 years ago

8 0

Answer:

Final Cost= 1.09(xx - .05xx)

Step-by-step explanation:

Since its 9% tax on the new price you would take the new price which would be 1.0 and add the .09 of tax. So its ×1.09 to get the tax.

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Jay took a number, n, and increased it by 25%. Then, he doubled the resulting product. Which of the following is equivalent to t

ruslelena [56]

Answer: Multiplying the number by 2.5

Step-by-step explanation:

Jay took a number, n, and increased it by 25%. The value gotten will be:

= n + (25% × n)

= n + (0.25 × n)

= n + 0.25n

= 1.25n

After that, Then, he doubled the resulting product. The value now gotten will be:

= 2 × 1.25n

= 2.50n

Therefore, the equivalent will be multiplying the number by 2.5. This will be:

= n × 2.5

= 2.5n

Therefore, it's thesame with the value gotten.

The correct option is D.

5 0

3 years ago

Find the length of each arc. Round your answer to the nearest tenth.

Ede4ka [16]

Answer:

give the full questions please

6 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

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3 years ago

7.5% sales tax on a $210 bracelet

kolbaska11 [484]

The total cost on the bracelet would be $225.75

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3 years ago

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What are factors of 30

Dennis_Churaev [7]

1,2,3,5,6,10,15,30 because by looking at the number at the ones place, when it is 0 or an odd number, it could be divided by 2. When the places are added together and when it is divisible by 3, it is the factor of 3. Also, when there are 2 and 3 as a factor, it is also divisible by 6.

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3 years ago