log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
#SPJ1
Answer:
option c is the answer for pic
and for question the answer is
(-274)*(437)
-119738
Answer:
all i know is that number #2 is A
adding it all up is hard to figure out but #2 will show you that lay out so it mite be easier but i need help on this as well
Step-by-step explanation:
Answer:
g(f(x)) = 3.15x
Step-by-step explanation:
To find the number of Japanese yen equivalent to x russian rubles, we need to put one function into another.
If we take f(x) and put in into g(x), we will get Japanese yen in terms of rubles. Thus,
g(f(x)) = 90 (0.035x)
g(f(x)) = 3.15x
THis is the composite function which represents the number of Japanese yen equivalent to x Russian Rubles.
17 since 51 goes into 3 17 times and 2 goes into 48 24 times and 17 is the largest number that can have 3 republicans and 2 democrats. The andwer would be 17 comittees,
