Based on your question that ask where each situation and the sampling frame doesn't match the population, resulting in under coverage. The possible answer to your question is , under coverage in a random sampling where the result that you get is still just a partial of the whole but it could be done in anytime as long as the number of people are still there. It means that the sampling result do not just base in one session of sampling.
Answer:
$ 75.
Step-by-step explanation:
From the information above,
List price of model II = $240
Sale price of the clearance sale is 1/4 off the list price of Model II microwave oven and additional 1/5 of the sale price for oven that are scratched and dented.
Therefore,
Let the sale price be X,
= (1/4)*(list price) + (1/5)*X
X = (1/4)*(240) + (1/5)*X
X = 60 + (1/5)X
Solving for X,
X - (1/5)X = 60
(4/5)X = 60
X = (60*5)/4
= $75.
I found out that t = 117 over 5
We know that both groups feed grass hay in the morning, so that's 100/100.
First group feeds alfalfa and grass in the evening
Second group feeds alfalfa and oat hay in the evening.
The estimated probability that horse owners feed grass hay the morning (AM) is 100%.
The estimated probability that horse owners feed alfalfa + oat hay in the pm is 28/100 or 28% (C)
I think it's (3) Calculate the nth term rule of the sequence
(I think
the answer to the equation is 8xy+36x+6y+9)
